Consider an RL circuit consisting of an inductor with an inductance of L henry(H)and aresistor with a resistance of R ohms (2) driven by a voltage of E(t) volts (V). Giventhe voltage drop across the resistor is ER = RI, and across the inductor isEL = L(dI / dt), Kirchhoff's Law givesNow suppose an RL circuit with a 3 resistor and a 0.03H inductor is driven by aconstant voltage of 90V. If the initial resistor current is I(0) = 0A, find the current Iand the voltages across the inductor EL and the resistorER in terms of time t.I(t)=ER(t)=dIL- + RI = E(t)dtEL(t) ==AVV

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Consider an RL circuit consisting of an inductor with an inductance of L henry(H)and a resistor with a resistance of Rohms () driven by a voltage of E(t) volts (V). Given the voltage drop across the resistor is ER RI, and across the inductor is E₁ = L(dI / dt), Kirchhoff's Law gives I(t) Now suppose an RL circuit with a 3 resistor and a 0.03H inductor is driven by a constant voltage of 90V. If the initial resistor current is I(0) = 0A, find the current I and the voltages across the inductor EL and the resistorER in terms of time t. = ER(t) EL(t) = = = dI L + RI = E(t) dt A V V

Consider an RL circuit consisting of an inductor with an inductance of L henry(H)and a resistor with a resistance of Rohms () driven by a voltage of E(t) volts (V). Given the voltage drop across the resistor is ER RI, and across the inductor is E₁ = L(dI / dt), Kirchhoff's Law gives I(t) Now suppose an RL circuit with a 3 resistor and a 0.03H inductor is driven by a constant voltage of 90V. If the initial resistor current is I(0) = 0A, find the current I and the voltages across the inductor EL and the resistorER in terms of time t. = ER(t) EL(t) = = = dI L + RI = E(t) dt A V V

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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