Learning Goal:To understand the magnetic force on a straight current-carrying wire in a uniform magnetic field.Part AMagnetic fields exert forces on moving chargedparticles, whether those charges are movingindependently or are confined to a current-carryingwire. The magnetic force F on an individual movingcharged particle depends on its velocity v and chargeq. In the case of a current-carrying wire, many chargedparticles are simultaneously in motion, so the magneticforce denends on the total current I and the lenath ofConsider a wire of length L = 0.30 m that runs north-south on a horizontal surface. There is a current ofI = 0.50 A flowing north in the wire. (The rest of the circuit, which actually delivers this current, is notshown.) The Earth's magnetic field at this location has a magnitude of 0.50 gauss (or, in Sl units,0.5 x 10-4 tesla) and points north and 38 degrees down from the horizontal, toward the ground. Whatis the size of the magnetic force on the wire due to the Earth's magnetic field? In considering theagreement of units, recall that 1T=1N/(A m).(Figure 1)Figure< 1 of 2Express your answer in newtons to two significant figures.?NUpW +SDownPart B Part BNow assume that a strong, uniform magnetic field of size 0.55 T pointing straight down is applied. Whatis the size of the magnetic force on the wire due to this applied magnetic field? Ignore the effect of theEarth's magnetic field.Express your answer in newtons to two significant figures.?N

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Answered: Consider a wire of length L = 0.30 m…

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