A point charge of value q = 3.10μC has a speed of = 2.14 × 107-1.81 × 10k when it is at the point (0.00 cm, 0.00 cm, 0.00 cm). We are interested in knowing the magnetic field at point (1.00cm, 1.00cm, 1.00cm). (a) what is the position vector R which points from the charge to the point of interest? (b) What is the unit vector  in component form? (c) What is the magnetic field vector in component form at position (1.00cm, 1.00cm, 1.00cm)? (d) A point charge of value q = 3.10μC has a speed of = -1.23 × 107+2.31 x 107 when it is at the point (1.00 cm, 0.00 cm,-1.00 cm). What is the magnetic field vector in component form at position (1.00cm, -1.00cm, 1.00cm)?

icon
Related questions
Question
**Problem Statement**

A point charge of value \( q = 3.10 \, \mu \text{C} \) has a speed of \( \vec{v} = 2.14 \times 10^7 \, \frac{m}{s} \, \hat{j} - 1.81 \times 10^7 \, \frac{m}{s} \, \hat{k} \) when it is at the point \( (0.00 \, \text{cm}, 0.00 \, \text{cm}, 0.00 \, \text{cm}) \). We are interested in knowing the magnetic field at point \( (1.00 \, \text{cm}, 1.00 \, \text{cm}, 1.00 \, \text{cm}) \). 

(a) What is the position vector \( \vec{R} \) which points from the charge to the point of interest?

(b) What is the unit vector \( \hat{R} \) in component form?

(c) What is the magnetic field vector in component form at position \( (1.00 \, \text{cm}, 1.00 \, \text{cm}, 1.00 \, \text{cm}) \)?

---

(d) A point charge of value \( q = 3.10 \, \mu \text{C} \) has a speed of \( \vec{v} = -1.23 \times 10^7 \, \frac{m}{s} \, \hat{j} + 2.31 \times 10^7 \, \frac{m}{s} \, \hat{k} \) when it is at the point \( (1.00 \, \text{cm}, 0.00 \, \text{cm}, -1.00 \, \text{cm}) \). What is the magnetic field vector in component form at position \( (1.00 \, \text{cm}, -1.00 \, \text{cm}, 1.00 \, \text{cm}) \)?

---

**Explanation**

- The position vector \( \vec{R} \) is determined by calculating the vector difference between the point of interest and the position of the charge.
- The unit vector \( \hat{R}
Transcribed Image Text:**Problem Statement** A point charge of value \( q = 3.10 \, \mu \text{C} \) has a speed of \( \vec{v} = 2.14 \times 10^7 \, \frac{m}{s} \, \hat{j} - 1.81 \times 10^7 \, \frac{m}{s} \, \hat{k} \) when it is at the point \( (0.00 \, \text{cm}, 0.00 \, \text{cm}, 0.00 \, \text{cm}) \). We are interested in knowing the magnetic field at point \( (1.00 \, \text{cm}, 1.00 \, \text{cm}, 1.00 \, \text{cm}) \). (a) What is the position vector \( \vec{R} \) which points from the charge to the point of interest? (b) What is the unit vector \( \hat{R} \) in component form? (c) What is the magnetic field vector in component form at position \( (1.00 \, \text{cm}, 1.00 \, \text{cm}, 1.00 \, \text{cm}) \)? --- (d) A point charge of value \( q = 3.10 \, \mu \text{C} \) has a speed of \( \vec{v} = -1.23 \times 10^7 \, \frac{m}{s} \, \hat{j} + 2.31 \times 10^7 \, \frac{m}{s} \, \hat{k} \) when it is at the point \( (1.00 \, \text{cm}, 0.00 \, \text{cm}, -1.00 \, \text{cm}) \). What is the magnetic field vector in component form at position \( (1.00 \, \text{cm}, -1.00 \, \text{cm}, 1.00 \, \text{cm}) \)? --- **Explanation** - The position vector \( \vec{R} \) is determined by calculating the vector difference between the point of interest and the position of the charge. - The unit vector \( \hat{R}
Expert Solution
Introduction:

Disclaimer: “Since you have asked posted a question with multiple sub-parts, we will solve the first three sub-parts for you. To get remaining sub-part solved please repost the complete question and mention the sub parts to be solved.”

We are given the charge. We are also given the velocity of charge.

The magnetic field by moving charge is given as

B=μo4πqv×rr3

Here q,v are charge and velocity respectively.

r is the position of point where field is to be calculated.

We first find this position vector. We then find the magnetic field. 

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

Blurred answer
Similar questions