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Consider a unity feedback control system with a plant G(s) = 10 s(s+4) Design a phase-lag compensator Gc(s) such that the static velocity error constant Kv is 50 sec¹ without appreciably changing the location of the original closed-loop poles, which are at s = -2±j√√6. Show the step responses of the uncompensated system and compensated system. Also compare ramp responses at the steady-state.

Consider a unity feedback control system with a plant G(s) = 10 s(s+4) Design a phase-lag compensator Gc(s) such that the static velocity error constant Kv is 50 sec¹ without appreciably changing the location of the original closed-loop poles, which are at s = -2±j√√6. Show the step responses of the uncompensated system and compensated system. Also compare ramp responses at the steady-state.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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2. Consider a unity feedback control system with a plant G(s) = 10 s(s+4) Design a phase-lag compensator Gc(s) such that the static velocity error constant Kv is 50 sec¹ without appreciably changing the location of the original closed-loop poles, which are at s = -2±j√6. Show the step responses of the uncompensated system and compensated system. Also compare ramp responses at the steady-state.
Transcribed Image Text:2. Consider a unity feedback control system with a plant G(s) = 10 s(s+4) Design a phase-lag compensator Gc(s) such that the static velocity error constant Kv is 50 sec¹ without appreciably changing the location of the original closed-loop poles, which are at s = -2±j√6. Show the step responses of the uncompensated system and compensated system. Also compare ramp responses at the steady-state.
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