Consider a triangular piece of diamond surrounded by air, as shown below. The index of refraction of diamond is na light ray enters the diamond normal to the bottom surface (surface 1), as shown. Can this light refract out of the diamond when it reaches surface 2? Explain why it can or cannot refract out. 2.42 and the index of refraction of air is nair = 1.00. The %3D 60° 2 30 1
Consider a triangular piece of diamond surrounded by air, as shown below. The index of refraction of diamond is na light ray enters the diamond normal to the bottom surface (surface 1), as shown. Can this light refract out of the diamond when it reaches surface 2? Explain why it can or cannot refract out. 2.42 and the index of refraction of air is nair = 1.00. The %3D 60° 2 30 1
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Transcribed Image Text:Consider a triangular piece of diamond surrounded by air, as shown below. The index of
refraction of diamond is na
light ray enters the diamond normal to the bottom surface (surface 1), as shown. Can this
light refract out of the diamond when it reaches surface 2? Explain why it can or cannot
refract out.
2.42 and the index of refraction of air is nair = 1.00. The
60°
30°
1
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