The figure shows a refracted light beam in linseed oil making an angle of o = 30.6° with the normal line NN'. The index of refraction of linseed oil is 1.48. Air N Linseed oil Water (a) Determine the angle 0. (b) Determine the angle 0'.
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Q: The figure shows a refracted light beam in linseed oil making an angle of p = 31.3° with the normal…
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Q: The light beam shown in the figure below makes an angle of = 24.0° with the normal line NN' in the…
A: Given data as per question Refractive index of linseed oil =1.48
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- 1) A light ray incoming from air hits a glass surface. Incident angle and refraction angle is calculated at the table below. a)Find the index of refraction of the medium for 3 different angles Incoming Refracted index N/A 30 8.7 45 12.2 60 15.3 b) Plot sin(theta1) vs sin(theta2) and obtain best fit line. What does the numeric value of the slope corresponds to in Snell's Law equation.The light beam shown in the figure below makes an angle of = 32.4° with the normal line NN' in the linseed oil. Determine the angles and 0'. (The refractive index for linseed oil is 1.48.) 0 = 0' = Air Linseed oil Waterou can determine the index of refraction of a substance by determining its critical angle. (a) What is the index of refraction of a substance that has a critical angle of 58.9° when submerged in ethanol, which has an index of refraction of 1.361?(b) What would the critical angle be for this substance in air? °
- A ray of light travelling through air encounters a 1.7-cm-thick sheet of glass at a 45 ∘ angle of incidence. Assume n = 1.5. How far does the light ray travel inside the glass before emerging on the far side?Express your answer in centimeters.(a) An opaque cylindrical tank with an open top has a diameter of 2.60 m and is completely filled with water. When the afternoon sun reaches an angle of 31.5° above the horizon, sunlight ceases to illuminate any part of the bottom of the tank. How deep is the tank (in m)? 4 Determine how the depth of the tank is related to the angle of refraction for the geometry described in the question. Drawing a diagram may be helpful. Then apply Snell's law to find the angle of refraction and use it to determine the depth of the water in the tank. m (b) What If? On winter solstice in Seattle, the sun reaches a maximum altitude of 19° above the horizon. What would the depth of the tank have to be (in m) for the sun not to illuminate the bottom of the tank on that day? m(a) The index of refraction for violet light in silica flint glass is 1.66, and that for red light is 1.62. What is the angular spread (in degrees) of visible light passing through a prism of apex angle 60.0° if the angle of incidence is 45.0°? See figure below. Visible light O Angular spread 0 Deviation of red light B V Screen R (b) What If? What is the angular spread (in degrees) of visible light passing through a prism of apex angle 60.0° if the angle of incidence is 90°?
- Needs Complete typed solution with 100 % accuracy.A ray of light in air is incident at an angle of 25.0° on a glass slide with index of refraction 1.46. (a) At what angle is the ray refracted? from the normal (b) If the wavelength of the light in vacuum is 535 nm, find its wavelength in the glass. nmRed light is incident in air on a 30° -60° - 90 ° prism as shown. The incident beam is directed at an angle of ₁ = 40.20 with respect to the horizontal and enters the prism at a height h = 20 cm above the base. The beam leaves the prism to the air at a distance d = 54.2 along the base as shown. 45.66 1.36 30⁰ 1) What is 2, the angle the beam in the prism makes with the horizontal axis? 71.9 d degrees Submit 2) What is n, the index of refraction of the prism for red light? dviolet d Submit Submit 02 3) What is 3, the angle the transmitted beam makes with the horizontal axis? h degrees Submit 03 degrees Submit (+) 4) What is 41,max, the maximum value of 1 for which the incident beam experiences total internal reflection at the horizontal face of the prism? degrees Submit + + 5) The red beam is now replaced by a violet beam that is incident at the same angle 1 and same height h. The prism has an index of refraction nviolet = 1.46 for violet light. Compare dviolet, the exit distance for…
- Light enters air from water. The angle of refraction will be O greater than the angle of incidence. O equal to the angle of incidence. O less than the angle of incidence.Geometric physics q 41A laser beam is incident on a 45°-45°-90° prism perpendicular to one of its faces, as shown in the figure below. The transmitted beam that exits the hypotenuse of the prism makes an angle of = 17.7° with the direction of the incident beam. Find the index of refraction of the prism. h Jē 45.0⁰