I would like a little more explanation on that please. That is an example given in a lecture. How did they come up with 31 different outcomes in A?P(A) = 1 – .59 = .41; so among a large number of such systems, roughly 41% will fail.What do they mean by that? Thank You. Consider a system of five identical components connectedin series, as illustrated in Figure 2.3.23415A system of five components connected in a seriesFigure 2.3Denote a component that fails by F and one that doesn'tfail by S (for success)Let A be the event that the system fails. For A to occur, atleast one of the individual components must fail.Copyright O Cengage Learning. All rights reserved. Outcomes in A include SSFSS (1, 2, 4, and 5 all work, but3 does not), FFSSS, and so on.There are in fact 31 different outcomes in A. However, A',the event that the system works, consists of the singleoutcome SSSSSWe will see in Section 2.5 that if 90% of all suchcomponents do not fail and different components failindependently of one another, thenP(A') P(SSSSS) .95 = 59.Thus P(A) 1 - .59 = .41; so among a large number ofsuch systems, roughly 41% will failCopyright O Cengage Learning. All rights reserved

Name: I would like a little more explanation on that please. That is an exam
Uploaded: 2024-03-20T07:07:00.000Z
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Description: I would like a little more explanation on that please. That is an example given in a lecture. How did they come up with 31 different outcomes in A?P(A) = 1 – .59 = .41; so among a large number of such systems, roughly 41% will fail.What do they mean