Consider a slightly different snippet of IA32 code:8048396: call 804839b804839b: retSuppose that just before the call instruction executes, the value stored in %esp is 0xffffd838. Then what is thevalue of %eip (the program counter) after the ret instruction executes?a. %eip=0x8048396b. %eip=0x804839bc. %eip-Oxffffd838d. %eip=0xffffd834

Dear Student, If no tampering occurred between the call and the ret, esp should be the same value as…

Consider a slightly ferent snippet 8048396: call 804839b 804839b: ret Suppose that just before the call instruction executes, the value store value of %eip (the program counter) after the ret instruction executes a. %eip=0x8048396

Consider a slightly ferent snippet 8048396: call 804839b 804839b: ret Suppose that just before the call instruction executes, the value store value of %eip (the program counter) after the ret instruction executes a. %eip=0x8048396

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Write an instruction that stores a half word value from x5 to the memory at address 394 (in decimal). Answer:
7
Python code, the code that I have is wrong. I am getting a error "'relative_error' is inaccurate"
Consider a slightly different snippet of IA32 code: 8048396: call 804839b 804839b: ret Suppose that just before the call instruction executes, the value stored in %esp is 0xffffd838. Then what is the value of %eip (the program counter) after the ret instruction executes? a. %eip=0x8048396 b. %eip=0x804839b c. %eip-Oxffffd838 d. %eip=0xffffd834
If DS=7F0OH, BX=37EH and AX=1F05H, find the value of (AL) after executing *:(XLAT) instruction, if you have the following memory contents 7AH 7F386H 66H 7F385H BOH 7F384H 79H 7F383H F4H 7F382H 8CH 7F381H 8CH вон 66H 79H 7AH F4H
B- Write a single instruction that loads AX from address 0200 H and DS from address 0202H.
The variable A is stored at memory address 24. We want to change its value to 512. Which of the following combinations of R5, R6, and the constant X will accomplish this with the instruction sw R6, X(R5)? Briefly explain. Note: more than one answer can be correct. Select and explain all that apply. 1. R6=512, X=0, R5=24 2. R6-512, X=24, R5=0 3. R6=24, X=512, R5=0 4. R6=24, X=0, R5=512
After the bitwise AND instruction is executed in the code sequence below, the final value of BX determines the values for the FLAGS. What is the value for the FLAGS? MOV BX, 91BAH AND BX, 91B2h Oa. a. CF= 0, ZF= 0, SF= 1, AF= 0, PF= 1. Ob. CF= 0, ZF= 0, SF= 1, AF= 1, PF= 1. Oc. CF= 0, ZF= 1, SF= 1, AF= 0, PF= 1. Od. CF= 1, ZF= 0, SF= 1, AF= 0, PF= 1.
6. What is the address of executing the following instruction: MOV CX, [FEH] if you know that DS= DC00H? OCL: DCOFEH, CH: DCOFFH OCL: DCFEH, CH: DCFFH CL: DCFFH, CH: DCFFH CL: DCOFFH, CH: DCOFFH
Write an optimal code that decrements the 32-bit signed value in DO by one if it is odd 02 01 Write a code segment that multiplies the 32-bit unsigned integer in DO by 247. Write a code that negates the signed 32-bit number in DO, assuming that the instruction set does not have negate
8086Mp memory is logically divided into segments, the size of each segment is: 1Mbyte 64Kbyte 128Kbyte 2Kbyte 10Kbyte 32Кbyte 1Kbyte Let CS=5A71H, IP=BF6CH. What is the name of the memory segment given in the following figure AFTER executing the instruction (CALL [BX+DI] )? if IPnew=8C23H. * BF H 6F80BH 6C H 6F80AH Extra segment Stack segment Code segment Data segment
Question 1 Write a MIPS assembly language program that collects all the '0' bits at the left edge and all the '1' bits at the right edge for a 32-bit number stored in register $a0. This output sequence should be stored in register $v0 and your program should finish in an infinite loop (a jump instruction that jumps to itself). For example: If $a0 contains 1111 0000 1111 0000 1111 0000 1111 0000 in binary (OXFOFOFOFO) the output sequence stored in $v0 with all the '0' bits moved to the left edge and all the '1' bits moved to the right edge should be as follows: 0000 0000 0000 0000 1111 1111 1111 1111 (0X0000FFFF)