Consider a right tailed test with a = 0.15. with a one-sided confidence bound at the 85% confidence level. If the observed test statistic was 1.136, what is the conclusion of this test. (a) The null hypothesis is rejected at the 85% confidence level (b) We fail to reject the null hypothesis at the 85% confidence level (c) We cannot find a conclusion based on the information given (d) None of the above
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- Right tailed
- Test statistic=1.136
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- 7Central Middle School has calculated a 95% confidence interval for the mean height (μ) of11-year-old boys at their school and found it to be 56 ± 2 inches.(a) Determine whether each of the following statements is true or false.• There is a 95% probability that μ is between 54 and 58.• There is a 95% probability that the true mean is 56, and there is a 95% chance thatthe true margin of error is 2.• If we took many additional random samples of the same size and from eachcomputed a 95% confidence interval for μ, approximately 95% of these intervalswould contain μ.• If we took many additional random samples of the same size and from eachcomputed a 95% confidence interval for μ, approximately 95% of the time μwould fall between 54 and 58.(b) Which of the following could be the 90% confidence interval based on the same data?• 56 ± 1• 56 ± 2• 56 ± 3• Without knowing the sample size, any of the above answers could be the 90%confidence interval.Suppose that you are testing the following hypotheses: Ho: p = .80 and Ha: p # .80. You calculate a test statistic value of z = -6.08. True or False: At a 95% confidence level, which is alpha = .05, you should reject the null hypothesis. True False
- Please provide solutions for both parts! ASAP.On average, 0(zero) is expected for the t statistic when the null hypothesis is true. Why? The value for an unknown population mean is estimated with a confidence interval using the t statistic? Why?Previous Problem List Next In order to compare the means of two populations, independent random samples of 237| observations are selected from each population, with the following results: Sample 1 Sample 2 2 1 12 s1 = 130 s2 175 (a) .Use a 971 % confidence interval to estimate the difference between the population means (41 – H2)! (b) . Test the null hypothesis: Ho : (41 - 42) = 0 versus the alternative hypothesis: H. : (41 – 42) + 0|. Using a = 0.03 give the following: (i) , the test statistic z = (ii) .the positive critical 21 score (ii) . the negative critical 21score The final conclustion is OA. We can reject the null hypothesis that (41 – 42) = 0 and accept that (1 – H2) + 0 OB. There is not sufficient evidence to reject the null hypothesis that (1 - H2) = 0 (c) . Test the null hypothesis: Ho : (u - 12) = 21| versus the alternative hypothesis: H, : (41 - 42) + 21. Using a = 0.03. give the following: (i) , the test statistic z = (ii) .the positive critical 2l score (ii) . the…
- If we REJECT the null hypothesis H0: μ=50 at the 0.05 significance level, then the 95% confidence interval for μ will NOT contain the value 50. True FalseA scientist claims that only 67% of geese in his area fly south for the winter. He tags 70 random geese in the summer and finds that 20 of them do not fly south in the winter. If α= 0.05, is the scientist's belief warranted? Test by using confidence interval. Round confidence interval to nearest thousandth. Show step1-step3 included conclusion.A sample of size n = 51 is drawn from a population whose standard deviation is o = 47. Part 1 of 2 (a) Find the margin of error for a 90% confidence interval for μ. Round the answer to at least three decimal plac The margin of error for a 90% confidence interval for u is Part 2 of 2 (b) If the sample size were n = 72, would the margin of error be larger or smaller? (Choose one) because the sample size is (Choose one) X 2022 McGraw Hill X 3 Ś Submit Assignment Terms of Use | Privacy Center | Accessibility