Consider a region of the shape of a rectangular box in the three dimensional coordinate system shown in the figure. Assuming that if there is an electric field of the form É = 2xi ,which of the following is the net electric flux through the region? ab 2ab abc 2abc

Q: Inside the region in the shape ( Rectangular box) there is no electric charge. The uniform electric…

A: In the given system having a rectangular box placed such that electric field is passing…

Q: Consider the uniform electric field E = (2.09 + 9.0k) x 103 N/C. What is its electric flux (in…

A: Given that :Electric field vector Radius of the circular area

Q: An electric field of magnitude equal to 8200 N/C is applied along the y-axis. Calculate the electric…

A: Given:- An electric field of magnitude equal to E = 8200 N/C is applied along the y-axis.  The side…

Q: Inside the region in the shape ( Rectangular box) there is no electric charge. The uniform electric…

A: According to Gauss’s law: ϕE=∫E.ds=Qencloseε0 Where,    ϕE= Electric flux.  E= Electric field.…

Q: A nonuniform electric field is given by the expression = - (3.00x² i + 5.00y j) N/C and passes…

A: Flux is the dot product of electric field and area vector. Area vector is always  perpendicular to…

Q: In a uniform electric field of magnitude E, the field lines cross through a rectangle of area A at…

A: The objective of the question is to calculate the electric flux through a rectangle in a uniform…

Q: An electric field E = (-2+x²)N/Cî passes through a cube of side a = 2m as shown in the figure. Find…

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Q: der the uniform electric field E = (4.0ĵ + 3.0k) × 10³ N/C. What is the electric agnitude through a…

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Q: Consider a region of the shape of a rectangular box in the three dimensional coordinate system shown…

A: Consider the Gauss's Law that, electric flux formula is, ϕ=qnecε0

Q: A closed surface with dimensions a=b=0.40 m and c=0.60 m is located as in the figure below. The left…

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Q: Two rings of radius R=8 cm are 50 cm apart and concentric with a common horizontal axis (figure…

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Q: The dimensions of a cone are displayed in the figure. As shown, the bottom face of the cone rests on…

A: electric fulx for a closed object is always =0 so here electric flux through the flat surcace(Ef) +…

Q: hich of the following statements about flux are true? The unit of flux is Vm²/C When turning a…

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Q: In the figure a solid sphere of radius a = 3.70 cm is concentric with a spherical conducting shell…

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Q: In the figure a solid sphere of radius a = 3.20 cm is concentric with a spherical conducting shell…

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Q: ingula or simplicity, only one field line is shown in the diagram below. b a sa (a) What is the…

A: Dimensions, a = 4.3 mm and b = 6.0 mm Field, E = 1400 N/C Angle, α = 42°

Q: If the electric flux through a sphere is 10.0 Nm^2/C, what is the electric flux through a sphere of…

A: Given: The electric flux through a sphere is ϕ1=10.0 Nm2/C,

Q: Calculate the absolute value of the electric flux for the following situations (In all case provide…

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Q: An electric flux of 144 N.m2/C passes through a flat horizontal surface that has an area of 0.72 m2.…

A: Electric flux through a surface (∅) = 144 N.m2 mCArea of surface (A) =0.72 m2Angle made by electric…

Q: Consider the uniform electric field E = (2.5 j + 2.5 k) × 103 N/C. a) Calculate the electric flux…

A: Given: The uniform electric filed E is (2.5 j⏜ + 2.5 k⏜)×103 N/C. The radius of the circular area in…

Q: Three charges of 3.4, 3.1 and -6.5 nC respectively are surrounded by a Gaussian surface in the shape…

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Q: In the figure a solid sphere of radius a = 3.20 cm is concentric with a spherical conducting shell…

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Q: 3. A thin insulating rod is bent into a semicircular arc of radius a, and a total electric charge Q…

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Q: A circular loop of wire with a diameter of 0.626 m is rotated in a uniform electric field to a…

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Q: An electric field given by E = 2.6 i – 6.1(y² + 6.2) j pierces the Gaussian cube of edge length 19.0…

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Q: disk of radius 196 mm is oriented with its normal unit vector n̂ at 60º to a uniform electric field…

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Q: he electric flux (Φ) that passes through this surface

A: we know electric flux ϕ = E·A =EAcosθ where θ= angle between electric field and area vector A = area…

Q: surface, as sha Calculate the electric flux through the surface.

A: Electric field Effect = 2000N/C Each side a= 2.8mm = 2.8x10-3 m Surface area A =(2.8x10-3)2 m2 =…

Q: The square surface shown in the figure measures 2.38 cm on each side. It is immersed in a uniform…

A: Here is the step-by-step explanation:Stepe 1: Use formula:We will use the formula, to calculate the…

Q: Consider a cylindrical surface in this electric field as shown in the figure. Electric field vector…

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Q: A flat sheet is in the shape of a rectangle with sides of lengths 0.2 m and 1.7 m. The sheet is…

A: Given that Length of the sheet L = 1.7 m Width of the sheet b = 0.2 m Uniform electric field E = 65…

Q: A Positive electric charge Q is distributed uniformly throughout the volume of an insulating solid…

A: Given  A charge Q is uniformly distributed over a solid sphere of radius a. We need to find the…

Q: The figure below shows a closed cylinder with cross-sectional area A 3.20 m². The constant electric…

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Q: A constant electric field of magnitude Eo points in the direction of the positive z-axis. What is…

A: The net flux through the cube depends on the field lines entering through a surface and leaving the…

Q: uniform electric field of magnitude E=435 N/C makes an angle of θ= 65.0 ° with a plane surface of…

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Q: The following charges are located inside a submarine: 3.10 μC, -9.00 μC, 27.0 μC, and -61 µC. (a)…

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Q: A flat surface of area 3.30 m² is rotated in a uniform electric field of magnitude E = 6.30 x 10³…

A: Given data: Area(A)=3.30 m2 Uniform Electric field (E)=6.30×10^5 N/C To find: (a) ϕperpendicular =…

Q: Consider a triangle in the presence of a uniform electric field given by 5.6 i N/C. The endpoints of…

A: Please see the answer below.

Q: A circular surface with a radius of 0.066 m is exposed to a uniform electric field of magnitude 1.90…

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Q: A charge distribution creates the following electric field throughout all space: E(r, 0, q) = (3/r)…

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