surface, as sha Calculate the electric flux through the surface.
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A: Given: Side a=5 cm=0.05 m Electric flux ϕ= 3*10^-5 Nm2/C To find the charge density on the sheet.
Electric field Effect = 2000N/C
Each side a= 2.8mm = 2.8x10-3 m
Surface area A =(2.8x10-3)2 m2 = 7.84x10-6 m2
Angel α = 35° normal to surface
α =180-35 =145°
Electric flux =Φ
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- 55 The following charge density function Po (1-r/R) for = R р elsewhere 0 describes a long cylindrical charge distribution figure out the electric field due to this charge distribution, everywhere.please do Q5Q1) given the spherical surfaces of (r=l m and r-5 m), curry charge densities of (-20 nC/m and 30 nC/m) respectively, find (i) D at r=2.5 m (ii) The total flux leaving the outer surface (r-5).