surface, as sha Calculate the electric flux through the surface.
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Question
![The square surface shown in the figure measures 2.8 mm on each side. It is immersed in a uniform electric field with magnitude E =
2000 N/C and with field lines at an angle of 35° with a normal to the surface, as shown. Take that normal to be "outward," as though the
surface were one face of a box. Calculate the electric flux through the surface.
Normal
****
Number
i
Units](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbb2d7a67-6d75-416b-9da5-8fd2246444f3%2F8a097d62-cca8-416c-b294-c454ba875401%2Fq16q61_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The square surface shown in the figure measures 2.8 mm on each side. It is immersed in a uniform electric field with magnitude E =
2000 N/C and with field lines at an angle of 35° with a normal to the surface, as shown. Take that normal to be "outward," as though the
surface were one face of a box. Calculate the electric flux through the surface.
Normal
****
Number
i
Units
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Given data
Electric field Effect = 2000N/C
Each side a= 2.8mm = 2.8x10-3 m
Surface area A =(2.8x10-3)2 m2 = 7.84x10-6 m2
Angel α = 35° normal to surface
α =180-35 =145°
Electric flux =Φ
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