Macmillan LearningConsider a parallel universe where the laws of nature are different, and aqueous solutions can have an excess charge. Twobeakers are separated 6.90 m and each contains 0.350 L of an aqueous solution of 3.10 x 10-6 M excess charge. One beaker hasa net positive charge, and one beaker has a net negative charge. Calculate the force between the beakers using the formulaF=1 91924xco ²where F is force, co is the permittivity constant and is equal to 8.85 x 10-12 C2/(N m²), q, is the charge contained in the firstbeaker, q2 is the charge contained in the second beaker, and r is the distance between the beakers. Note that I mole of charge is96485 C. Because one of the beakers contains a net negative charge, one q will be negative, and F will be negative. A negativeF corresponds to an attractive force.F=-1.63 x106IncorrectN

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Consider a parallel universe where the laws of nature are different, and aqueous solutions can have an excess charge. Two beakers are separated 6.90 m and each contains 0.350 L of an aqueous solution of 3.10 x 10-6 M excess charge. One beaker has a net positive charge, and one beaker has a net negative charge. Calculate the force between the beakers using the formula F= 1 9192 Ancor where F is force, co is the permittivity constant and is equal to 8.85 x 10-12 C²/(N m²). q, is the charge contained in the first beaker, q2 is the charge contained in the second beaker, and r is the distance between the beakers. Note that I mole of charge is 96485 C. Because one of the beakers contains a net negative charge, one q will be negative, and F will be negative. A negative F corresponds to an attractive force. F= -1.63 x10 Incorrect N

Consider a parallel universe where the laws of nature are different, and aqueous solutions can have an excess charge. Two beakers are separated 6.90 m and each contains 0.350 L of an aqueous solution of 3.10 x 10-6 M excess charge. One beaker has a net positive charge, and one beaker has a net negative charge. Calculate the force between the beakers using the formula F= 1 9192 Ancor where F is force, co is the permittivity constant and is equal to 8.85 x 10-12 C²/(N m²). q, is the charge contained in the first beaker, q2 is the charge contained in the second beaker, and r is the distance between the beakers. Note that I mole of charge is 96485 C. Because one of the beakers contains a net negative charge, one q will be negative, and F will be negative. A negative F corresponds to an attractive force. F= -1.63 x10 Incorrect N

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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