The figure below shows three small, charged spheres, all lying along the horizontal axis. Sphere A, at left, has a 5.20 nC charge. Sphere B has a 1.60 nC charge and is 3.00 cm to the right of A. Sphere C has a -2.10 nC charge and is 2.00 cm to the right of B. Find the magnitude (in N) and direction of the net electric force on each of the spheres. Net Force on A magnitude direction Net Force on B magnitude direction Net Force on C magnitude direction 9₁ 3.00 cm ---Select--- --Select--- ---Select--- N N N qB qc 2.00 cm-> i
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A: qA = 1.90μCqB = 5.40μC qC = -5.20μC each side of triangle = 0.50 m
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- Three charges are at the corners of an isosceles triangle as shown in the figure (Figure 1). The ±5.00 μC charges form a dipole. Part A Find the magnitude of the force the -10.00 μC charge exerts on the dipole. Part B Find the direction of the force the -10.00 μC charge exerts on the dipole.(Suppose that y y -axis directs to the top of the image.) ∘ counterclockwise from the +y - directionThree point charges are located on the positive x-axis of a coordinate system. Charge q1 = +1.0nC is 4.0cm from the origin, charge q2 = -3.0nC is 6.0cm from q1 and charge q3 = 5.0nC located at the origin. Solve for the following: a. What is the total force exerted by these three charges on a charge q4 = -4.0nC located midway between q1 and q2? b. If q4 is moved 3cm to the right of q2, what is the total force exerted by these three charges on q4?124. The charge per unit length on the thin rod shown below is 2. What is the electric force on the point charge q? Solve this problem by first considering the electric force dF on q due to a small segment dx of the rod, which contains charge idx. Then, find the net force by 25 integrating d F over the length of the rod.
- The figure below shows three small, charged beads, all lying along the horizontal axis. Bead A, at left, has a 6.65 nC charge. Bead B has a 1.10 nC charge and is 3.00 cm to the right of A. Bead C has a -2.05 nC charge and is 2.00 cm to the right of B. 3.00 cm qB direction -2.00 cm 9c (a) What is the magnitude (in N/C) of the electric field at a point 2.00 cm to the right of A? 18625 X Draw the directions of the electric field vectors, due to each of the three charges, at the point to the right of A. What are the signs of the charges? How does this affect the directions of the field vectors? What is the magnitude of the electric field due to a point charge? Add the fields as vectors to get the net field. Be careful with units and signs. N/C (b) A fourth bead with a charge of -8.00 nC is placed at this point. What are the magnitude (in N) and direction of the net electric force on it? magnitude 14.9 X From part (a), what is the electric field at the given point? If we place a charged…Given the arrangement of charged particles in the figure below, find the net electrostatic force on the q1 = 6.05-µC charged particle. (Assume q2 = 15.33 μC and q3 = -21.12 µC. Express your answer in vector form.) N 91 (-2.00 cm, 0) 93 (1.00 cm, 1.00 cm) 92 (0, -1.00 cm)Four charged particles are placed at corners of a square as shown in the figure. Find the magnitude and direction of the net electric force on -5.00 nC charge. k = 9.00 x 10⁹ Nm² C2 3.0 nC -4.0 nC 1.0 cm -5.0 nC 1.0 cm + 3.0 nC 280.9 x 10-5 N, 45° South of West 280.9 x 10-5 N, 45° North of East 180 x 10-5 N, 45° South of West 101 x 10-5 N, 45° South of West 10.9 x 10-5 N, 45° South of West 180 x 10-5 N, 45° North of East 101 x 10-5 N, 45° North of East 10.9 x 10-5 N, 45° North of East West North South East
- A positively charged particle Q1 = 25 nC is held fixed at the origin. A negatively charged particle Q2 = -16 nC of mass m = 7.5 μg is located a distance d = 45 cm from the positively charged particle along the positive x-axis. a. What is the magnitude of the electric force, F in newtons, that acts on the charge Q2? b. What is the direction of the force on charge Q2? c. What is the magnitude of the acceleration, a in m/s2, experienced by charge Q2?Three point charges lie initially along a straight line. A 2 nC charge is in the middle, with a 1 nC charge 6 cm to its right, and a 4 nC charge 6 cm to its left. a. What is the force of the 4 nC charge on the 2 nC charge? b) What is the force of the 1 nC charge on the 2 nC charge? c) What is the total force on the 2 nC charge? d) To where, if anywhere other than infinitely far away, and with the other charges not moving, would you move the 2 nC charge so that the total force on it was zero?Q1. A charge of -3.0 µC is located at the origin; a charge of 4.0 uC is located at x = 0.2 m, y=0; a third charge Q is located at x =0.32, y=0. The force on the 4.0 uC charge is 240 N, directed in the positive x direction. a) Determine the charge Q.
- Two charged particles are a distance of 1.82 m from each other. One of the particles has a charge of 7.31 nC, and the other has a change of 4.62 nC. a) What is the magnitude (in N) of the electric force that one particle exerts on the other?Consider three-point charges located at the corners of a right triangle as shown in Figure below, where q1 = q3 = 5.0 x10 -6C, q2 = 2.0 x 10-6C, and a= 0.10 m. A. Find the resultant force exerted on q3. B.Determine the magnitude of force exerted on q3 .Three point charges are arranged as shown in the figure below. 5.00 nC -3.00 nC 0.300 m 0.100 m Ⓡ (a) Find the vector electric field that the q = 6.50 nC and -3.00 nC charges together create at the origin. X Your response differs from the correct answer by more than 10%. Double check your calculations. N/C Î + (b) Find the vector force on the 5.00 nC charge. UN Î+ UN Ĵ N/Cĵ