Consider a hypothetical machine with the following characteristics: a. instruction format ; (total of 12 bits, LSB is bit 0, MSB is bit 11) Opcode (4 bits) Address ( 8 bits) b. internal CPU registers: PC (Program Counter) – holds the address of the instruction IR (Instruction register) – holds the instruction to be executed A- temporary storage B- temporary storage. c. partial list of opcodes M- memory address 0000 – STA M- store A to memory M 0001– LDA M- load A from memory M 0011- STB M- store B to memory M 0101 – LDB M - load B from memory M 1000 - ADDA M – add data in M to A 1010 – ADDAB – add B to A note : IR contains both the opcode and address; A and B are 8-bit registers; data at memory location 20 is 05; data at memory location 30 is 08; all numbers are in hex; answers should be in hex; Given the program segment below: LDA 20 LDB 30 ADDAB Questions: 1. What will be the contents of IR after fetching instruction 1? 2. What will be the contents of IR after fetching instruction 2? 3. What will be the contents of register A after instruction 3? 4. What will be the contents of register B after instruction 3? 5. Write the machine instruction that will copy the result of ADDAB instruction to location 50.

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