Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 5762 patients treated with this drug, 165 developed the adverse reaction of nausea. Use a 0.01Ksignificance level to test the claim that 3% of users develop nausea. Does nausea appear to be a problematic adverse reaction?Identify the null and alternative hypotheses for this test. Choose the correct answer below.OA. Ho: p=0.03H₁: p<0.03OB. Ho: p=0.03H₁: p>0.03C. Ho: p=0.03H₁: p*0.03OD. H₂:p*0.03H₁: p=0.03Identify the test statistic for this hypothesis test.The test statistic for this hypothesis test is(Round to two decimal places as needed)View an example Get more help.3EDCBO$4RFPRV%5TGB6MacBook AirfoYH&7NכСNJ8M-K(9HдвI8O-OLd810P. Vリ....Clear allcommand optiondFIT{[?111ICheck answer15spunWYE}1deleteret

n=5762x=165 Thus, p^=xn=1655762p^=0.0286

Answered: Consider a drug that is used to help…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the mean GPA of night students is significantly different than 2.4 at the 0.2 significance level.The null and alternative hypotheses would be: H0:p=0.6H0:p=0.6H1:p≠0.6H1:p≠0.6 H0:μ=2.4H0:μ=2.4H1:μ≠2.4H1:μ≠2.4 H0:μ=2.4H0:μ=2.4H1:μ>2.4H1:μ>2.4 H0:p=0.6H0:p=0.6H1:p<0.6H1:p<0.6 H0:μ=2.4H0:μ=2.4H1:μ<2.4H1:μ<2.4 H0:p=0.6H0:p=0.6H1:p>0.6H1:p>0.6 The test is: right-tailed left-tailed two-tailed Based on a sample of 31 people, the sample mean GPA was 2.36 with a standard deviation of 0.16The p-value is: (to 3 decimals)The positive significance level is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Identify the type I error and the type II error that corresponds to the given hypothesis. The proportion of adults who use the internet is greater than 0.27. Which of the following is a type I error? O A. Reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually 0.27. O B. Fail to reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually different from 0.27. O C. Reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually different from 0.27. O D. Fail to reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually 0.27. Which of the following is a type II error? O A. Fail to reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually 0.27. O B. Reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is…
State the Result: A hypothesis test was conducted at the alpha = 0.01 level of significance. The test resulted in a p-value of 0.044.
You are conducting a study to see if the probability of a true negative on a test for a certain cancer is significantly different from 0.85. You use a significance level of α=0.002α=0.002. H0:p=0.85H0:p=0.85 H1:p≠0.85H1:p≠0.85You obtain a sample of size n=415n=415 in which there are 361 successes.What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value =
A claim is given. Select the corresponding null hypothesis and using a significance level of α = 0.05 and the given p-value, determine if you reject the null hypothesis or fail to reject the null hypothesis. Claim: Americans spend on average less than 8 minutes in the shower. Data: In a sample of Americans (n = 1,803), the average time spent in the shower is 7.8 minutes with a p-value of 0.0546. A. H0 :μ=8and we reject the null. B. H0 :μ=8and we fail reject the null. C. H0 :μ>8and we reject the null. D. H0 :μ>8and we fail reject the null. E. H0 :μ<8and we reject the null. F. H0 :μ<8and we fail reject the null.
You are conducting a study to see if the probability of a true negative on a test for a certain cancer is significantly different from 0.34. You use a significance level of α=0.005α=0.005. H0:p=0.34H0:p=0.34 H1:p≠0.34H1:p≠0.34You obtain a sample of size n=551n=551 in which there are 164 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value =
In a study of the accuracy of fast food drive-through orders, one restaurant had 38 orders that were not accurate among 335 orders observed. Use a 0.10 significance level to test the claim that the rate of inaccurate orders is equal to 10%. Does the accuracy rate appear to be acceptable? Identify the null and alternative hypotheses for this test. Choose the correct answer below. Ho:p = 0.1 H4:p#0.1 O B. Ho: p#0.1 H1:p=0.1 OC. Ho: p=0.1 H:p0.1 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is 0.82 (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer. Final Check parts 2 remaining Clear All MacBook Pro 4) トII トト 88 F10 F7 F9 esc F3 F5 F4 F1 F2 @ 2$ % & delete 2 3 4 6. 7 8 Q W E T Y tab F G K A S caps lock くつ DI
Suppose you want to test the claim that μ = 3.5. Given a sample size of n = 35 and a level of significance of a = 0.10 when should you reject Ho? This represents a The curve. hypothesis represents the claim. Reject Ho if the standardized test statistic is 10 or
In the test of hypothesis H0:μ=100 vs . Ha:μ≠100, we already have the p-value for this test: P-value=0.025. Which of the following (with the reason) will be correct with significance level at .05? The information is not enough to make a decision. Reject H0 since the P-value is less than the significance level. Reject H0 since the P-value is greater than .01. Fail to reject H0 since the P-value is greater than .01. Fail to reject H0 since the P-value is less than the significance level.

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