Consider a double pendulum consists of two-point masses m which are connected by strings of length / as shown in the figure below. Determine canonical momenta associated with the coordinates e and e,. Answer Choices: P, = 2ml è + mf ė̟ cos (@ – e.) a. P. = ml0, +ml*ė¸ cos(6, – 6,) P. - 2ml ė, + ml°è̟ cos (A – e.) b. P. = mfè, + ml° è, cos(6, – 0,) P. = ml è, + m² è̟ cos (A – e.) P. = ml'è, + ml*è¸ cos(6 – e, ) P. = mf è +ml*è̟ cos (@ - 8.) с. d. P. - 2ml*ė, +ml*è¸ cos( & – 6, )
Consider a double pendulum consists of two-point masses m which are connected by strings of length / as shown in the figure below. Determine canonical momenta associated with the coordinates e and e,. Answer Choices: P, = 2ml è + mf ė̟ cos (@ – e.) a. P. = ml0, +ml*ė¸ cos(6, – 6,) P. - 2ml ė, + ml°è̟ cos (A – e.) b. P. = mfè, + ml° è, cos(6, – 0,) P. = ml è, + m² è̟ cos (A – e.) P. = ml'è, + ml*è¸ cos(6 – e, ) P. = mf è +ml*è̟ cos (@ - 8.) с. d. P. - 2ml*ė, +ml*è¸ cos( & – 6, )
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![Consider a double pendulum consists of two-point masses m which are connected by
strings of length / as shown in the figure below. Determine canonical momenta associated
with the coordinates a and 0,.
Answer Choices:
P, = 2ml'è +mfè̟cos(e - e,)
Pa = mFè, +ml*0, cos(e, -e,)
P, = 2ml'ė, + mi è cos(e -6.)
a.
b.
Pa = mFe, + ml*è, cos(e, -e,)
Pa = ml'è, + mt è̟ cos(e - e.)
C.
P = ml'6, + ml*6 cos (e -e,)
Pa = mfà +ml è̟ cos(4 - e.)
d.
P. = 2ml*0, + mľ²0, cos( e - e,)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F030e43b9-50fb-4967-82c4-4f59d05f40cb%2F9e816d88-a2a6-4c40-aa8e-bb92be046d20%2Fh0rj1fl_processed.png&w=3840&q=75)
Transcribed Image Text:Consider a double pendulum consists of two-point masses m which are connected by
strings of length / as shown in the figure below. Determine canonical momenta associated
with the coordinates a and 0,.
Answer Choices:
P, = 2ml'è +mfè̟cos(e - e,)
Pa = mFè, +ml*0, cos(e, -e,)
P, = 2ml'ė, + mi è cos(e -6.)
a.
b.
Pa = mFe, + ml*è, cos(e, -e,)
Pa = ml'è, + mt è̟ cos(e - e.)
C.
P = ml'6, + ml*6 cos (e -e,)
Pa = mfà +ml è̟ cos(4 - e.)
d.
P. = 2ml*0, + mľ²0, cos( e - e,)
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