A thin rod of length L and mass m has a linear density X(x) = Ax² where A is a constant and is the distance from the rod's left end. Locate the rod's center of mass (from x = = 0) in terms of its length by filling in the missing factor below.
A thin rod of length L and mass m has a linear density X(x) = Ax² where A is a constant and is the distance from the rod's left end. Locate the rod's center of mass (from x = = 0) in terms of its length by filling in the missing factor below.
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![**Computation**
A thin rod of length \( L \) and mass \( m \) has a linear density \( \lambda(x) = Ax^2 \) where \( A \) is a constant and \( x \) is the distance from the rod's left end. Locate the rod’s center of mass (from \( x = 0 \)) in terms of its length by filling in the missing factor below.
[Hint: In terms of \( A \) and \( L \), the rod’s mass is \( M = \int_0^L \lambda \, dx \). Evaluate that integral and substitute into the denominator of the center of mass definition:
\[ x_{cm} = \frac{\int_0^M x \, dm}{\int_0^M \, dm} = \frac{\int_0^L x \lambda(x) \, dx}{M} \]
The constant \( A \) will cancel and you’ll be left with an answer proportional to \( L \).]
\[ x_{cm} = \, \_\_\_\_\_ \, L \]
Record your numerical answer below, assuming three significant figures. Remember to include a “-" when necessary.
[Blank space provided for answer]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F047a7e6a-f025-4b5b-ab83-4ffe14f69253%2F558f2983-dfc5-4d28-85ca-77b50995b035%2F81gqbjh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Computation**
A thin rod of length \( L \) and mass \( m \) has a linear density \( \lambda(x) = Ax^2 \) where \( A \) is a constant and \( x \) is the distance from the rod's left end. Locate the rod’s center of mass (from \( x = 0 \)) in terms of its length by filling in the missing factor below.
[Hint: In terms of \( A \) and \( L \), the rod’s mass is \( M = \int_0^L \lambda \, dx \). Evaluate that integral and substitute into the denominator of the center of mass definition:
\[ x_{cm} = \frac{\int_0^M x \, dm}{\int_0^M \, dm} = \frac{\int_0^L x \lambda(x) \, dx}{M} \]
The constant \( A \) will cancel and you’ll be left with an answer proportional to \( L \).]
\[ x_{cm} = \, \_\_\_\_\_ \, L \]
Record your numerical answer below, assuming three significant figures. Remember to include a “-" when necessary.
[Blank space provided for answer]
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