Consider a circult where an ideal inductor L=0.144H is connected in parallel to a resistor R=1.00kn. This combination is connected in series with a capacitor C=3.67e-07F. This combination in connected to a power supply source of frequency f-3.4kHz. To study this circuit you need to draw a phasor diagram. Note the sum of the current phasors through the resistor and the inductor must be equal to the phasor representing the current through the capacitor (i.e. the total current). You should draw the phasor for the current through the capacitor on the horizontal axis, since this is also the total current delivered by the supply. The angle between this phasor and that of the power supply represents the phase angle . Note that the voltage across the inductor equals the voltage across the resistor since they connected parallel to each other. Furthermore the sum of the phasors representing the currents through the inductor and the resistor equals the phasor representing the current through the capacitor. Remember that the current through the resistor is in phase with the voltage across the resistor; and the current through the inductor lags the voltage across the inductor by 90 degrees. a) What is the phase angle A between the current through the resistor and the current through the capacitor? Ix degrees b) From the phasor diagram calculate the total impedance of the circult? You will need to relate the x and y components of the phasor representing the power supply to the x and y components of the phasors representing the voltages across the resistor and capacitor. z,= x ohms c) What is the voltage across the capacitor in terms of the power supply voltage, Vg? x Vs d) If the amplitude of the power supply is V-14.0 volts, what is the amplitude of the voltage V,? One possible approach is to use the phasor diagram for the voltages and the law of cosines. You can also figure out I, and multiply by R. VR- x V e) What is the current (in mA) through the capacitor? x MA f) What is the phase angle e between the power supply voltage and the current through the capacitor? A positive value means the power supply voltage leads the cumrent and a negative value means the current leads the voltage. x degrees 9) Calculate the power dissipated by the resistor. PR x watts h) Calculate the power delivered by the power supply. X watts Pe=