Concentrationt of [Fe(CN)6]3- (M) Concentrationt of C6H806 Trial Absorbance Rate (s1) (M) At 20.00 s: .538 1 40.0009875 ,005209 40 .00885 At 40.00 s: 40 361 At 20.00 s: .269 40.0009875 49.0002605 x 40.0044 2 At 40.00 s: .181 At 20.00 s: D .269 3 40.0004938 D.005209 40.0044 At 40.00 s: 40.181
Concentrationt of [Fe(CN)6]3- (M) Concentrationt of C6H806 Trial Absorbance Rate (s1) (M) At 20.00 s: .538 1 40.0009875 ,005209 40 .00885 At 40.00 s: 40 361 At 20.00 s: .269 40.0009875 49.0002605 x 40.0044 2 At 40.00 s: .181 At 20.00 s: D .269 3 40.0004938 D.005209 40.0044 At 40.00 s: 40.181
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
How to find rate law and write it?
![Use the data to set up a method of initial rates table. Calculate new diluted concentrations based on reaction mixtures and use the absorbance at time 20s and 40s to calculat
Concentrationt of
[Fe(CN)6]3-
(M)
Concentrationt of
C6H806
(M)
Trial
Absorbance
Rate (s1)
At 20.00 s: 4.0
.538
1
4.0
.0009875
4.0
.005209
4.0
.00885
At 40.00 s: 4.0 .361
At 20.00 s: 4.0
.269
2
4.0
.0009875
4.0
0002605 X
4.0
.0044
At 40.00 s: 4.0
.181
At 20.00 s: 4.0
.269
3
4.0
.0004938
4.0
.005209
4.0
.0044
At 40.00 s: 4.0
.181
TRemember: these are the concentrations of A, B, C, or D after they have been mixed together for reaction.
The Rate Law
Calculate the orders of reaction with respect to the two reactants. Use the logarithms method.
Order With Respect to
Order With Respect to
C6H806
[Fe(CN)6]3-
Calculatedt
Rounded to
4.0
4.0
More Information. More Information.
Nearest Integer
#Enter to at least two decimal places.
Write the rate law for the reaction. Rate laws take the general form: rate =
k. [H20]² . [S04²-]
chemPad
Help
X. x° →=-
Greek -](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1593f45e-4da7-40d4-bc81-735ecba0bfae%2Fc09834ad-2035-4f56-83c6-8b2f8620cad5%2Fj2ccfz_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Use the data to set up a method of initial rates table. Calculate new diluted concentrations based on reaction mixtures and use the absorbance at time 20s and 40s to calculat
Concentrationt of
[Fe(CN)6]3-
(M)
Concentrationt of
C6H806
(M)
Trial
Absorbance
Rate (s1)
At 20.00 s: 4.0
.538
1
4.0
.0009875
4.0
.005209
4.0
.00885
At 40.00 s: 4.0 .361
At 20.00 s: 4.0
.269
2
4.0
.0009875
4.0
0002605 X
4.0
.0044
At 40.00 s: 4.0
.181
At 20.00 s: 4.0
.269
3
4.0
.0004938
4.0
.005209
4.0
.0044
At 40.00 s: 4.0
.181
TRemember: these are the concentrations of A, B, C, or D after they have been mixed together for reaction.
The Rate Law
Calculate the orders of reaction with respect to the two reactants. Use the logarithms method.
Order With Respect to
Order With Respect to
C6H806
[Fe(CN)6]3-
Calculatedt
Rounded to
4.0
4.0
More Information. More Information.
Nearest Integer
#Enter to at least two decimal places.
Write the rate law for the reaction. Rate laws take the general form: rate =
k. [H20]² . [S04²-]
chemPad
Help
X. x° →=-
Greek -
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