For the reversible reactionN2(g)+O2(g)2NO(g)the concentrations at equilibrium are [N2] = 0.17 M and [O2] = 0.44 M, and K = 2.1 × 10–3. Find [NO] at equilibrium.

Answered: concentrations at equilibrium

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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For the reversible reaction

N2(g)+O2(g)2NO(g)

the concentrations at equilibrium are [N₂] = 0.17 M and [O₂] = 0.44 M, and K = 2.1 × 10^–3. Find [NO] at equilibrium.

Expert Solution

Step 1

Equilibrium constant for any reaction at equilibrium is the ratio of product of concentrations of product side to product of concentration at reactant side raised to power of molecules in which react.

For the given reaction,

N₂(g) + O₂(g) $\to$ 2NO(g)

Value of K = [NO]² / [N₂]*[O2]

As we know K is a ratio of 2 similar quantities, therefore it is a unitless quantity.

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