Concentration of Cu in unknown (penny) = (from calibration curve) Mass of Cu in sample (penny) = Recall that the volume of the solution obtained by dissolving the penny is 250.00 mL (0.25000 L). To calculate the mass of Cu in the penny, you will first need to calculate the moles of Cu. This is done by multiplying the concentration of Cu (in moles/L) by the volume (0.25000 L). Finally, multiplying the moles of Cu by the molar mass of Cu (in g/mole) yields the mass of Cu in the original sample. %3D Percent Cu in penny =

Concentration of Cu in unknown (penny) = (from calibration curve) Mass of Cu in sample (penny) = Recall that the volume of the solution obtained by dissolving the penny is 250.00 mL (0.25000 L). To calculate the mass of Cu in the penny, you will first need to calculate the moles of Cu. This is done by multiplying the concentration of Cu (in moles/L) by the volume (0.25000 L). Finally, multiplying the moles of Cu by the molar mass of Cu (in g/mole) yields the mass of Cu in the original sample. %3D Percent Cu in penny =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: How many microliters of original sample are required to produce a final dilution of 102 in a total…

A: according to Dilution law initial = final M1V1 = M2V2 final dilution = M2 / M1 =10-2 (given)…

Q: 14.1 mL of 0.134 M Pb(NO3)2 is mixed with 12.9 mL of 0.324 M KI. Calculate the final concentration…

A: Answer:When solutions of two different substance are mixed and formation of precipitate takes place…

Q: [References] Use the References to access important values if needed for this question. In the…

Q: Eight hydrochloric acid solutions were titrated and the concentration was determined to be as listed…

A: We know that 1 M = 1000 mM

Q: A. Dilution of Stock Solution Concentration of STOCK solution you prepared (M) 0.8 Volume of STOCK…

A: Introduction: This can be calculated from the equivalence formula, V1S1 = V2S2 (V and S are the…

Q: Volume vinegar used (ml) % from label Molarity of NaOH Titration volume measurements Inital volume…

A: Molarity of titrant, NaOH used = 0.0987 M The balanced equation for the reaction is: NaOH(aq) +…

Q: Use the lab introduction to answer the following question. When answering this problem, report the…

A: Volume of beverage powder sample mixture = 3.78 L Volume of sample taken for dilution (V1) = 10 mL…

Q: STARTING AMOUNT Determine the total volume in milliliters of water a chemist should add if they want…

Q: 1. Vinegar is a solution of acetic acid (the solute) in water (the solvent) with a solution density…

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: When 20.00 ml of sulfuric acid of unknown concentration is titrated with 0.1249 M NaOH, 32.50 ml of…

Q: a solution by dilution

Q: [References) Use the References to access important values if needed for this question. In the…

Q: Calculate the molar concentration for each of the following solutions A. 2.00 g KCl in 95.0 mL of…

A: Molar concentration can be calculated as follows

Q: Question 25 of 46 Convert the concentration of 0.700 M Na,SO, to g/ml STARTING AMOUNT ADD FACTOR…

Q: At your next lab assignment, you are instructed to prepare 250 mL of 0.500 mol/L HCl by dilution of…

Q: A burette had an initial volume of 5.2 mL and a final volume of 32.6 mL, what is the amount of…

A: Given data is as follows: The initial reading of the burette V1= 5.2 mL The final reading of the…

Q: None

A: Step 1:Molarity (M) = volumeofsolution(L)molesofsolute= volumeofsolution(mL)mmolesofsolute Step 2…

Q: A chemist needs to determine the concentration of a sulfuric acid solution by titration with a…

Q: The mass of calcium sulfide that is dissolved in 225 mL of a saturated solution is _____ gram

A: Solubility product is a product of the concentration of ions with the power when the solution is…

Q: You decide to dissolve 56.00 g of teal nickel (II) sulfate in enough water to make 850 mL of…

A: Concentration, otherwise called Molarity is found out by using the following formula- No of moles of…

Q: Calculating 12.49 mg. KI in 104.5mL of solution

A: Molarity is the ratio of moles of solute to volume of solution in litres. Molarity=no. of moles of…

Q: A student needs to dilute a 0.38 M Pb(NO,), solution to make 97.0 mL of 0.22 M Pb(NO,),. Set up the…

Q: Determine the total volume in milliliters of water a chemist should add if they want to prepare an…

Q: You then use the standardized NAOH (0.1736 M) to determine the unknown concentration of an acetic…

A: The equation for unknown values is given by, M1V1=M2V2 where M is the molarity and V is the volume.

Q: What's the concentration of my solution if I dissolved 1 penny in 50 mL of nitric acid. I did that…

Q: In the next part of the experiment, you used the standard solution of sodium oxalate to standardize…

A: The data given is,

Q: Perform the following calculations for your procedure: 1. To prepare a 100.0-mL 4.00 mM Fe³+…

A: We need to prepare 100.0 mL of 4 mM Fe3+ solution from the FeCl3 solid.

Q: I need to calculate the Molarity of the solution. I am attaching what I thought I needed to do but…

A: Molarity = number of mols of solute / volume of solution in liter

Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

PART B. Spectrophotometric Determination of the Copper Content of a Penny
Mass of penny: 3.1848
Date on penny: 1964
Concentration of standard Cu2 solution:
M
Volume, Standard Volume, 1 M
[Cu] (M) % Transmittance Absorbance
Cu (mL)
HNO, (mL)
(use Eq. 4)
2.
O.06
84.3%
Test tube 1
0-074
O.IS
60.95% 0.215
Test tube 2
8.
3
0 244
45.3%
0.344
Test tube 3
300M
33.65%
Standard
O.473
Unknown
52.822
0-277

Concentration of Cu in unknown (penny) =
(from calibration curve)
%3D
Mass of Cu in sample (penny) =
Recall that the volume of the solution obtained by dissolving the penny is 250.00 mL (0.25000 L).
To calculate the mass of Cu in the penny, you will first need to calculate the moles of Cu. This is done
by multiplying the concentration of Cu (in moles/L) by the volume (0.25000 L). Finally, multiplying
the moles of Cu by the molar mass of Cu (in g/mole) yields the mass of Cu in the original sample.
Percent Cu in penny =
Remember that percent by mass is simply the mass of Cu in the sample divided by the total mass
of the sample (x 100%).
Show your calculations in the space below. Attach the calibration curve to this page.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Calculating mass of copper in sample

VIEW

Calculating percent Cu in penny

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 6 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

29.91 ml of an acid solution (identity unknown) is neutralized by 17.29 ml of 0.1999 M calcium hydroxide solution. Determine the Normality of the acid.
I'm a bit confused with this one. thank you
there isn’t a block for .155 … Can you please help line them up exactly in the correct order and exact unit that are in the bank below?
Give Detailed Solution with explanation (don't give Handwritten answer
It takes 14.7 mL of 7.46 x 10-1 M sodium hydroxide to reach equivalence with 8.8 mL of an unknown molarity acid. Determine the molarity of the acid. Record your answer to three decimal places.(
You may want to reference (Pages 306 - 308) Section 9.5 while completing this problem. Part A Determine the volume, in milliliters, required to prepare each of the following diluted solutions. 23.0 mL of a 0.250 M KNO3 solution from a 6.50 M KNO3 solution Express your answer with the appropriate units. HÁ Value Units Submit Request Answer Part B 28.0 mL of a 2.50 M H2SO4 solution from a(n) 12.4 M H2SO4 solution Express your answer with the appropriate units. HA ? Value Units
hi, is one able to help with this please?
You have been asked to make 250.0 mL of a 0.100 M solution of calcium nitrate. A. Calculate the mass (in g) of solid calcium nitrate needed to make the solution.
If 31.0 mLmL of a 0.200 NN acid solution is needed to reach the end point in titration of 24.5 mLmL of a base solution, what is the normality of the base solution?
Volume of HCL sample = 15ml Molarity standardized NaOh solution = .09929 Initial buret reading = 17.85 mL NaOH final buret reading = 36.16 mL NaOH volume of NaOH used = 17.31 Equation HCl = NaOH=NaCl + H2O How many moles of NaOH were used to reach the equivalence point?
15.0 mL of 17.2 M NaNO3 is diluted to 100.0 mL. What is the molarity of the new solution? __________ M (Report your answer with the correct sig figs in units of moles/ L, M