Con For each chemical reaction listed in the first column of the table below, predict the sign (positive or negative) of the reaction entropy AS If it's not possible to decide with the information given, check the "not enough information" button in the last column. Note for advanced students: Assume the temperature remains constant. Assume all gases and solutions are ideal. reaction 2014(e)+70, (e) 4CO₂(g) + 6H₂0(e) Za(s) + 2HCl(ag) ZaC1₂(aq) + H₂(e) sign of reaction entropy <0 O 45 0 450 O not enough information. 045 <0 045 0 not enough information. 048 <0 rin CaCl, (aq) + Na, CO, (a) CaCO,(s) + 2NaCl(a) 450 O not enough information,

Con For each chemical reaction listed in the first column of the table below, predict the sign (positive or negative) of the reaction entropy AS If it's not possible to decide with the information given, check the "not enough information" button in the last column. Note for advanced students: Assume the temperature remains constant. Assume all gases and solutions are ideal. reaction 2014(e)+70, (e) 4CO₂(g) + 6H₂0(e) Za(s) + 2HCl(ag) ZaC1₂(aq) + H₂(e) sign of reaction entropy <0 O 45 0 450 O not enough information. 045 <0 045 0 not enough information. 048 <0 rin CaCl, (aq) + Na, CO, (a) CaCO,(s) + 2NaCl(a) 450 O not enough information,

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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For each chemical reaction listed in the first column of the table below, predict the sign (positive or negative) of the reaction entropy A.Sxn If it's not possible to decide with the information given, check the "not enough information" button in the last column. Note for advanced students: Assume the temperature remains constant. Assume all gases and solutions are ideal. reaction H₂O(/) + AL₂ S₂ (s) → H₂S (g) + Al₂O₂ (s) 2C₂H, (g) + 70₂(g) → 4CO₂(g) + 6H₂O(g) BaCl₂ (aq) + K₂SO4 (aq) BaSO₂ (s) + 2K Cl(aq) sign of reaction entropy AS rxn AS rxn not enough information. AS 0 X 0 rxn not enough information. 3
53. Please show the process of cancelling out the function of ln. thank you
The standard reaction free energy AG=-1482. kJ for this reaction: 4 Fe(s) + 30₂(g) 2 Fe₂O3(s) Use this information to complete the table below. Round each of your answers to the nearest kJ. reaction 2Fe₂O₂ (s) 4Fe(s) + 30, (g) - Fe(s) + O₂(g) → Fe₂03 (s) Fe₂O₂ (s) → Fe(s) + 0₂ (8) AG kJ kJ X 5
Predict whether AS for each reaction would be greater than zero, less than zero, or too close to zero to decide. Clear All H2(g) + F2(g)- →2HF(g) →2NO(g) + Br2(g) 2NOBr(g)- AS > 0 CO2(g) + H2(g)- + H20(g) →CO(g) AS < 0 2CO2(g) + 5H2(g)- C,H2(g) + 4H,0(g) too close to decide 2H2021)2H,0(1) + 02(g)
2H2O(g) ----> 2H2(g) + O2(g) The reaction above is only spontaneous at temperatures above 2000K. Is the reaction endothermic (+ΔH) or exothermic (-ΔH)?
W ↑ To determine the spontaneity of a chemical reaction, the sign of AG rather than the sign of AS is generally used. This is because O (1) AG is always positive and AS may be positive or negative O (2) Free energy free and it is easier to understand than entropy. O (3) AG is always larger than AS O (4) none given #3 3 A Moving to the next question prevents changes to this answer. E C $ 4 D R G Search or type URL % 5 MacBook Pro T (O G Y & 7 H U * 8 J 9 K 0 1 L Questi P
The products have higher entropy than the reactants explain why 2C2H6 (g) + 7O2 (g) —> 4CO2 (g) + 6H2O (g)
What is the free energy change at 25oC for the reaction below, if the standard entropies of reactants and products are So (C(gr)) = 5.74 J/mol*K, So(H2(g)) = 130.68 J/mol*K, and So (C4H10(g)) = 310.1000 J/mol*K and the heat of formation of C4H10(g) is -126.1400 kJ/mol.4C(gr) + 5H2(g) ↔ C4H10(g) ΔGo = -16.995 kJ ΔGo = 16.995 kJ ΔGo = 235.285 kJ ΔGo = -235.285 kJ
1:44 1 LTE 4 1 Search Question 20.b of 23 Show Answer Consider the reaction Cl2(g) + Br2(g) → 2 BrCI(g) at 25 °C. Which of the following best explains why the change in entropy is so small? A) All of the components in the chemical equation are gases. B) There are the same moles of gas on both sides of the reaction. C) The temperature of the reaction does not change. Tap here or pull up for additional resources
Enter your answer in the provided box. Calculate the standard entropy change for the following reaction at 25°C. 2 Al(s) + 3 ZnO(s) → Al₂O3(s) + 3 Zn(s) Substance Al(s) Al³+ (aq) Al₂O3(s) Zn(s) Zn²+ (aq) ZnO(s) J/K Sº (J/K mol) 28.3 -313.38 50.99 41.6 -106.48 43.9 27
2 For the synthesis of ammonia where AG = -33.3 kJ/mole, determine whether the reaction is spontaneous at 25 C with the following pressures: PN, = 1.0 atm, PH, = 3.0 atm, PNH, = 0.020 atm N2(8) + 3H2(g) = 2NH3(g)
A cvg.cengagenow.com Flipgrid | 50ffc. GRLContent Netflix Favorites My Home 3-Day General.. Netflix Content [Review Topics] [References] 2req Use the References to access important values if needed for this question. 2req The free energy change for the following reaction at 25 °C, when [H*] = 7.21×10³ M and [Hg²*]=1.17 M, is 178 kJ: 2req 2H*(7.21×10-3 M) + Hg(1)→ H,(g) + Hg²*(1.17 M) AG= 178 kJ What is the cell potential for the reaction as written under these conditions? s 2req Answer: V ts 2req Would this reaction be spontaneous in the forward or the reverse direction? ots OM) pts 2reg Submit Answer Retry Entire Group 9 more group attempts remaining pts M) pts