CHALLENGE 7.5.2: Function definition: Volume of a pyramid with modular functions. ACTIVITY Define a function calc_pyramid_volume() with parameters base_length, base_width, and pyramid_height, that returns the volume of a pyramid with a rectangular base. calc_pyramid_volume() calls the given calc_base_area() function in the calculation. Relevant geometry equations: Volume = base area x height x 1/3 Sample output with inputs: 4.5 2.1 3.0 Volume for 4.5 2.1 3.0 is: 9.45 Learn how our autograder works 461710.3116374.qx3zqy7 1 def calc_base_area(base_length, base_width): return base_length* base_width Your solution goes here 234 5 | 6 7 8 9 length float(input()) 10 width float(input()) = = - 111 11 height = float(input()) 12 print (f'Volume for {length} {width} {height} is: {calc_pyramid_volume (length, width, height):.2f}

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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CHALLENGE 7.5.2: Function definition: Volume of a pyramid with modular functions.
ACTIVITY
Define a function calc_pyramid_volume() with parameters base_length, base_width, and pyramid_height, that returns the volume of
a pyramid with a rectangular base. calc_pyramid_volume() calls the given calc_base_area() function in the calculation.
Relevant geometry equations:
Volume = base area x height x 1/3
Sample output with inputs: 4.5 2.1 3.0
Volume for 4.5 2.1 3.0 is: 9.45
Learn how our autograder works
461710.3116374.qx3zqy7
1 def calc_base_area(base_length, base_width):
return base_length* base_width
Your solution goes here
234
5 |
6
7
8
9 length float(input())
10 width float(input())
= =
-
111
11 height = float(input())
12 print (f'Volume for {length} {width} {height} is: {calc_pyramid_volume (length, width, height):.2f}
Transcribed Image Text:CHALLENGE 7.5.2: Function definition: Volume of a pyramid with modular functions. ACTIVITY Define a function calc_pyramid_volume() with parameters base_length, base_width, and pyramid_height, that returns the volume of a pyramid with a rectangular base. calc_pyramid_volume() calls the given calc_base_area() function in the calculation. Relevant geometry equations: Volume = base area x height x 1/3 Sample output with inputs: 4.5 2.1 3.0 Volume for 4.5 2.1 3.0 is: 9.45 Learn how our autograder works 461710.3116374.qx3zqy7 1 def calc_base_area(base_length, base_width): return base_length* base_width Your solution goes here 234 5 | 6 7 8 9 length float(input()) 10 width float(input()) = = - 111 11 height = float(input()) 12 print (f'Volume for {length} {width} {height} is: {calc_pyramid_volume (length, width, height):.2f}
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