Compute the heat, change in internal energy, and work for the cycle of two moles of a hypothetical ideal gas taken around the cycle ABCA where: Process AB is isochoric, BC is isobaric, and CA is isothermal. Show the solution. Given: Cv = 20.8 J/mol K State Pressure Volume Temperature A 5 x 105 Pa 6.6*10-3 m3 198 K B 3 x 105 Pa 6.6*10-3 m3 119 K C 3 x 105 Pa 11 x 10-3 m3 198 K Answer Keys: Q = -365.8 J ∆U = 0 for a cycle W = -365.8 J
Compute the heat, change in internal energy, and work for the cycle of two moles of a hypothetical ideal gas taken around the cycle ABCA where: Process AB is isochoric, BC is isobaric, and CA is isothermal. Show the solution. Given: Cv = 20.8 J/mol K State Pressure Volume Temperature A 5 x 105 Pa 6.6*10-3 m3 198 K B 3 x 105 Pa 6.6*10-3 m3 119 K C 3 x 105 Pa 11 x 10-3 m3 198 K Answer Keys: Q = -365.8 J ∆U = 0 for a cycle W = -365.8 J
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Compute the heat, change in internal energy, and work for the cycle of two moles of a hypothetical ideal gas taken around the cycle ABCA where: Process AB is isochoric, BC is isobaric, and CA is isothermal. Show the solution.
Given: Cv = 20.8 J/mol K
State |
Pressure |
Volume |
Temperature |
A |
5 x 105 Pa |
6.6*10-3 m3 |
198 K |
B |
3 x 105 Pa |
6.6*10-3 m3 |
119 K |
C |
3 x 105 Pa |
11 x 10-3 m3 |
198 K |
Answer Keys: Q = -365.8 J
∆U = 0 for a cycle
W = -365.8 J
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