Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column. 3 0 4 3 4 3 0 4 -1 Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. Simplify your answer.) O A. Using this expansion, the determinant is (0)(- 3)– (4)(– 3) + (4)(- 3) = O B. Using this expansion, the determinant is - (0)(- 3)+ (4)(- 3)– (4)(– 3) = Oc. Using this expansion, the determinant is (3)(- 16) – (0)(- 3) + (4)(12) = O D. Using this expansion, the determinant is - (3)(– 16) + (0)(-3) – (4)(12)=
Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column. 3 0 4 3 4 3 0 4 -1 Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. Simplify your answer.) O A. Using this expansion, the determinant is (0)(- 3)– (4)(– 3) + (4)(- 3) = O B. Using this expansion, the determinant is - (0)(- 3)+ (4)(- 3)– (4)(– 3) = Oc. Using this expansion, the determinant is (3)(- 16) – (0)(- 3) + (4)(12) = O D. Using this expansion, the determinant is - (3)(– 16) + (0)(-3) – (4)(12)=
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column.
3 0
4
3 4
0 4 - 1
Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice.
(Simplify your answer.)
O A. Using this expansion, the determinant is (0)(- 3)- (4)(- 3)+ (4)(– 3) =
B. Using this expansion, the determinant is - (0)(- 3) + (4)(– 3) - (4)(– 3) =
C. Using this expansion, the determinant is (3)(- 16) - (0)(- 3)+ (4)(12) =
D. Using this expansion, the determinant is - (3)(- 16) + (0)(– 3) – (4)(12) =
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