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Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column. 3 -3 4 1 1 4 -2 Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) O A. Using this expansion, the determinant is -(-3)(-9)+(1)(– 10) – (4)(- 3) = O B. Using this expansion, the determinant is - (3)(– 14) +(– 3)(- 9) – (4)(11)=| OC. Using this expansion, the determinant is (- 3)(- 9) – (1)(- 10) + (4)( – 3) =| O D. Using this expansion, the determinant is (3)(– 14)– (- 3)(-9) + (4)(11)=| Compute the determinant using a cofactor expansion down the second column. Select the correct choice below and fill in the answer box to complete your choice.

Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column. 3 -3 4 1 1 4 -2 Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) O A. Using this expansion, the determinant is -(-3)(-9)+(1)(– 10) – (4)(- 3) = O B. Using this expansion, the determinant is - (3)(– 14) +(– 3)(- 9) – (4)(11)=| OC. Using this expansion, the determinant is (- 3)(- 9) – (1)(- 10) + (4)( – 3) =| O D. Using this expansion, the determinant is (3)(– 14)– (- 3)(-9) + (4)(11)=| Compute the determinant using a cofactor expansion down the second column. Select the correct choice below and fill in the answer box to complete your choice.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column. 3 - 3 4 1 1 4 - 2 ... Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) O A. Using this expansion, the determinant is - (- 3)(- 9)+ (1)(- 10) - (4)(- 3) = B. Using this expansion, the determinant is - (3)(- 14) + (- 3)(– 9) – (4)(11) = C. Using this expansion, the determinant is (- 3)(- 9) – (1)(– 10) + (4)( – 3) = D. Using this expansion, the determinant is (3)(– 14) - (- 3)(- 9) + (4)(11)= Compute the determinant using a cofactor expansion down the second column. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) O A. Using this expansion, the determinant is - (- 3)(- 9)+ (1)(- 10) - (4)(- 3) = B. Using this expansion, the determinant is (3)(- 14) – (- 3)(– 9) + (4)(11) = Oc. Using this expansion, the determinant is (- 3)(– 9) – (1)(– 10) + (4)( – 3) =
Transcribed Image Text:Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column. 3 - 3 4 1 1 4 - 2 ... Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) O A. Using this expansion, the determinant is - (- 3)(- 9)+ (1)(- 10) - (4)(- 3) = B. Using this expansion, the determinant is - (3)(- 14) + (- 3)(– 9) – (4)(11) = C. Using this expansion, the determinant is (- 3)(- 9) – (1)(– 10) + (4)( – 3) = D. Using this expansion, the determinant is (3)(– 14) - (- 3)(- 9) + (4)(11)= Compute the determinant using a cofactor expansion down the second column. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) O A. Using this expansion, the determinant is - (- 3)(- 9)+ (1)(- 10) - (4)(- 3) = B. Using this expansion, the determinant is (3)(- 14) – (- 3)(– 9) + (4)(11) = Oc. Using this expansion, the determinant is (- 3)(– 9) – (1)(– 10) + (4)( – 3) =
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