Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column. 30 3 w w 3 4 3 0 4 1 Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) O A. Using this expansion, the determinant is (3)(-16)+(0)(-3) - (3)(12) = B. Using this expansion, the determinant is (0)(-3) (4)(-3)+(4)(0)=· O C. Using this expansion, the determinant is (3)(-16)-(0)(-3) + (3)(12) = D. Using this expansion, the determinant is -(0)(-3) + (4)( − 3) − (4)(0) =|
Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column. 30 3 w w 3 4 3 0 4 1 Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) O A. Using this expansion, the determinant is (3)(-16)+(0)(-3) - (3)(12) = B. Using this expansion, the determinant is (0)(-3) (4)(-3)+(4)(0)=· O C. Using this expansion, the determinant is (3)(-16)-(0)(-3) + (3)(12) = D. Using this expansion, the determinant is -(0)(-3) + (4)( − 3) − (4)(0) =|
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the
second column.
30 3
w w
3 4 3
0 4 1
Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to
complete your choice.
(Simplify your answer.)
O A. Using this expansion, the determinant is (3)(-16)+(0)(-3) - (3)(12) =
B. Using this expansion, the determinant is (0)(-3) (4)(-3)+(4)(0)=·
O C. Using this expansion, the determinant is (3)(-16)-(0)(-3) + (3)(12) =
D. Using this expansion, the determinant is -(0)(-3) + (4)( − 3) − (4)(0) =|
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