Compound A (C1,H14) shows prominent peaks in its mass spectrum at m/z 134 and 91. Compound B (also C10H14) shows prominent peaks at m/z 134 and 119. On vigorous oxidation with chromic acid, compound A gave benzoic acid, but compound B was nonreactive. From this information, deduce the structures of both compounds, and then draw the structure of A.

Compound A (C1,H14) shows prominent peaks in its mass spectrum at m/z 134 and 91. Compound B (also C10H14) shows prominent peaks at m/z 134 and 119. On vigorous oxidation with chromic acid, compound A gave benzoic acid, but compound B was nonreactive. From this information, deduce the structures of both compounds, and then draw the structure of A.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

(a) Compound A has molecular formula C5H10O. It shows three signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.1 ppm, a singlet of integral 3 at 2.14 ppm, and a quintet of integral 1 at 2.58 ppm. Suggest a structure for A and explain your reasoning. (b) Compound B has molecular formula C8H6O2. The IR, 1H-NMR, and 13C-NMR spectra are shown below, they are also downloadable for closer inspection by clicking the link under the spectral data. Suggest a structure for B and explain your reasoning. (c) Compound C has molecular formula C5H8O. The IR, mass, 1H-NMR, and 13C-NMR spectra are shown below, they are also downloadable for closer inspection by clicking the link under the spectral data. Suggest a structure for C and explain your reasoning.
Give answer of the attachment ?
Compound A exhibits two signals in its 1H NMR spectrum at 2.64 and 3.69 ppm, and the ratio of the absorbing signals is 2:3. Compound B exhibits two signals in its 1H NMR spectrum at 2.09 and 4.27 ppm, and the ratio of the absorbing signals is 3:2. Which compound corresponds to dimethyl succinate, and which compound corresponds to ethylene diacetate?
2. The compound with the closed formula C4H9Br gives the following 1H NMR data. Write the clear formula of the compound with reasons. 1.0 ppm (triplet, 3 H); 1.7 ppm (dublet, 3H); 1.8 ppm (multiplet, 2H); 4.2 ppm (multiplet, 1H)
Loudon | Parise SEVENTH EDITION presented by Macmillan Learning Propose a structure for an amine of formula C,H,N, which liberates a gas when treated with NaNO, and HCl. The 13C NMR spectrum is given, with attached protons in parentheses. 13C NMR: 8 14 (2), 8 34.3 (2), 8 50.0 (1)
How could 1H NMR spectroscopy be used to distinguish between each pair of compounds?
A compound has a formula of C19H16- Five signals appear in its 1°C NMR spectrum-one at 57 ppm and the remaining four between 126 and 144 ppm. In its 'H NMR spectrum, an unresolved multiplet (15 H) appears between 6.9 and 7.44 ppm and a singlet (1 H) appears at 5.5 ppm. What is the structure of this compound?
(b) The 1H-NMR spectrum of compound B, C5 H10 O2, consists of the following signals: 8 1.2 (d, 6H), 2.0 (s, 3H), and 5 (septet, 1H); contains an ester. Draw the structural formula of compound B. • You do not have to consider stereochemistry. • Explicitly draw all H atoms. ୫) C n ? ChemDoodle ® Show Hint
Cc.18.
asap with explanation
Identify the structures of each compound from the given data.
None