Can you help me on this worksheet? I know the how to do the Electric Configuration. Thank you in advance!! I really appreciate it! Complete the table below.ElectronicDistribution Last sublevelQuantumnumbers ofElementOrbitalQuantumnumbers of lastOrbitalElectronconfiguration diagram of last(last writtenelectronicConfigurationWrite the electronicconfiguration in theformat below:1s? 2s² 3s² 4s²2p° 3p°3dsof e- in thediagram ofspecificelectronconfigurationof specificelectronmainspecificelectronsublevelelectron in theenergy levelconfigurationlast sublevelconfigurationn = 31= 2configuration)Example:K = 2Electron # 9L = 8n=2MnM = 133ds|t1111 ml = 21 = 12p25N= 2ms = + ½ml = 0ms =- ½Electron # 17Cd48Electron # 53Ir77Electron # 26Ga31Electron # 49Sm62

48Cd Electronic configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 Arranging in the format…

Complete the table below. Element Electronic Distribution Last sublevel Orbital Quantum numbers of last Quantum numbers of Orbital Electron configuration diagram of last (last written electronic diagram of specific electron Configuration Write the electronic configuration in the format below: 1s² 2s² 3s? 4s² 2p 3p% 3ds of e- in the configuration of specific electron main sublevel electron in the last sublevel specific electron energy level configuration configuration) configuration n= 3 |1=2 Example: K=2 Electron # 9 L= 8 n=2 1= 1 ml = 0 ms = - ½ M= 13 3ds 11111 ml = 2 2p Mn 25 N=2 0 = ms = + ½ Electron # 17 Cd 48 Electron # 53 Ir 77 Electron # 26 Ga 31 Electron # 49 Sm |62

Complete the table below. Element Electronic Distribution Last sublevel Orbital Quantum numbers of last Quantum numbers of Orbital Electron configuration diagram of last (last written electronic diagram of specific electron Configuration Write the electronic configuration in the format below: 1s² 2s² 3s? 4s² 2p 3p% 3ds of e- in the configuration of specific electron main sublevel electron in the last sublevel specific electron energy level configuration configuration) configuration n= 3 |1=2 Example: K=2 Electron # 9 L= 8 n=2 1= 1 ml = 0 ms = - ½ M= 13 3ds 11111 ml = 2 2p Mn 25 N=2 0 = ms = + ½ Electron # 17 Cd 48 Electron # 53 Ir 77 Electron # 26 Ga 31 Electron # 49 Sm |62

Chemistry for Engineering Students

3rd Edition

ISBN:9781285199023

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter1: Introduction To Chemistry

Section: Chapter Questions

Problem 1.77PAE

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