**Organic Chemistry Reaction Road Map****Objective:**Complete the road map problem shown below by drawing the product of each step of the reaction sequence in the boxes.**Reaction Sequence Start:**- Starting Compound: Cyclopentene (a five-membered ring with one double bond)**Step 1:**- Reagent: HBr in ether- Product: Bromocyclopentane (the double bond is broken, and a hydrogen and a bromine atom are added across the double bond)**Step 2:**- Reagent: Mg^0 in ether- Product: Grignard Reagent (cyclopentyl magnesium bromide, where magnesium inserts itself between the cyclopentyl group and the bromine atom)**Step 3:**- Reagent: 1) (an aldehyde or ketone)- Reagent: 2) H_3O^+- Product: (the Grignard reagent reacts with the carbonyl compound to form a new carbon-carbon bond, followed by protonation to yield a secondary or tertiary alcohol)**Step 4:**- Reagent: PCC (Pyridinium Chlorochromate)- Product: (the secondary alcohol is oxidized to a ketone)**Final Compound:**- Cyclopentyl ethyl ketone**Step-by-Step Detailed Explanation of Each Reaction:**1. **Electrophilic Addition Reaction:** - Cyclopentene reacts with HBr in ether to form bromocyclopentane. The double bond is broken, a hydrogen atom is added to one carbon, and a bromine atom is added to the adjacent carbon.2. **Grignard Reaction Formation:** - Bromocyclopentane reacts with magnesium in ether to form the Grignard reagent, cyclopentyl magnesium bromide, creating a structure where magnesium is bonded to the carbon formerly bonded to bromine.3. **Nucleophilic Addition with Grignard Reagent:** - The Grignard reagent reacts with an aldehyde or ketone, followed by hydrolysis (H_3O^+) to form a tertiary or secondary alcohol, respectively.4. **Oxidation Reaction:** - The resultant alcohol is oxidized using PCC to form a ketone.Make sure to show clear intermediate structures and to follow the progression of each reaction step when completing the reaction road map.

The reaction of an alkene with HBr in presence of ether forms alkyl halide product by the addition…

Answered: Complete the road map problem shown…

Complete the road map problem shown below by drawing the product of each step of the reaction sequence in the boxes. HBr Mg° ether ether 1) 2) H3O* OH РСС

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Reactions of Ethers

Ethers (R-O-R’) are compounds formed by replacing hydrogen atoms of an alcohol (R-OH compound) or a phenol (C6H5OH) by an aryl/ acyl group (functional group after removing single hydrogen from an aromatic ring). In this section, reaction, preparation and behavior of ethers are discussed in the context of organic chemistry.

Epoxides

Epoxides are a special class of cyclic ethers which are an important functional group in organic chemistry and generate reactive centers due to their unusual high reactivity. Due to their high reactivity, epoxides are considered to be toxic and mutagenic.

Williamson Ether Synthesis

An organic reaction in which an organohalide and a deprotonated alcohol forms ether is known as Williamson ether synthesis. Alexander Williamson developed the Williamson ether synthesis in 1850. The formation of ether in this synthesis is an SN2 reaction.

Question

**Organic Chemistry Reaction Road Map**

**Objective:**
Complete the road map problem shown below by drawing the product of each step of the reaction sequence in the boxes.

**Reaction Sequence Start:**
- Starting Compound: Cyclopentene (a five-membered ring with one double bond)

**Step 1:**
- Reagent: HBr in ether
- Product: Bromocyclopentane (the double bond is broken, and a hydrogen and a bromine atom are added across the double bond)

**Step 2:**
- Reagent: Mg^0 in ether
- Product: Grignard Reagent (cyclopentyl magnesium bromide, where magnesium inserts itself between the cyclopentyl group and the bromine atom)

**Step 3:**
- Reagent: 1) (an aldehyde or ketone)
- Reagent: 2) H_3O^+
- Product: (the Grignard reagent reacts with the carbonyl compound to form a new carbon-carbon bond, followed by protonation to yield a secondary or tertiary alcohol)

**Step 4:**
- Reagent: PCC (Pyridinium Chlorochromate)
- Product: (the secondary alcohol is oxidized to a ketone)

**Final Compound:**
- Cyclopentyl ethyl ketone

**Step-by-Step Detailed Explanation of Each Reaction:**
1. **Electrophilic Addition Reaction:**
- Cyclopentene reacts with HBr in ether to form bromocyclopentane. The double bond is broken, a hydrogen atom is added to one carbon, and a bromine atom is added to the adjacent carbon.

2. **Grignard Reaction Formation:**
- Bromocyclopentane reacts with magnesium in ether to form the Grignard reagent, cyclopentyl magnesium bromide, creating a structure where magnesium is bonded to the carbon formerly bonded to bromine.

3. **Nucleophilic Addition with Grignard Reagent:**
- The Grignard reagent reacts with an aldehyde or ketone, followed by hydrolysis (H_3O^+) to form a tertiary or secondary alcohol, respectively.

4. **Oxidation Reaction:**
- The resultant alcohol is oxidized using PCC to form a ketone.

Make sure to show clear intermediate structures and to follow the progression of each reaction step when completing the reaction road map.

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