Complete the equations for the given equilibria, and calculate Keq where Species pKa Species pKa the Keq expression includes [H,O]. Be sure to enter Keq in proper 35 H,0 NH, 15.74 scientific notation. NH 9.25 H,O* -1.74 Ammonia (acting as a base) reacts with water (acting as an acid). equation: NH, + H,0 = NH† + OH- Keg = Ammonia (acting as an acid) reacts with water (acting as a base). equation: NH, + H,0= Keq = Which reaction is more important (i.e., prevalent) in an aqueous solution of ammonia? ammonia acting as a base ammonia acting as an acid O O

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**Organic Chemistry: Acid-Base Equilibria of Ammonia**

*Presented by Macmillan Learning*

**Instructions:**
Complete the equations for the given equilibria and calculate \( K_{eq} \) where the \( K_{eq} \) expression includes \([H_2O]\). Be sure to enter \( K_{eq} \) in proper scientific notation.

**Reactions:**

1. **Ammonia acting as a base reacts with water (acting as an acid).**

   - **Equation:** \( \text{NH}_3 + \text{H}_2\text{O} \rightleftharpoons \text{NH}_4^+ + \text{OH}^- \)

   - **\( K_{eq} = \) [Calculate and enter result here]

2. **Ammonia acting as an acid reacts with water (acting as a base).**

   - **Equation:** \( \text{NH}_3 + \text{H}_2\text{O} \rightleftharpoons \) [Complete the equation]

   - **\( K_{eq} = \) [Calculate and enter result here]

**Determine Reaction Prevalence:**
Which reaction is more important (i.e., prevalent) in an aqueous solution of ammonia?

- [ ] ammonia acting as a base
- [ ] ammonia acting as an acid

**Data Table:**

- **Species \(pK_a\):**
  - \( \text{NH}_3 \): 35
  - \( \text{NH}_4^+ \): 9.25
  - \( \text{H}_2\text{O} \): 15.74
  - \( \text{H}_3\text{O}^+ \): -1.74

Use this information to solve the given problems and understand the concepts of acid-base equilibria in the context of ammonia's reactions with water.
Transcribed Image Text:**Organic Chemistry: Acid-Base Equilibria of Ammonia** *Presented by Macmillan Learning* **Instructions:** Complete the equations for the given equilibria and calculate \( K_{eq} \) where the \( K_{eq} \) expression includes \([H_2O]\). Be sure to enter \( K_{eq} \) in proper scientific notation. **Reactions:** 1. **Ammonia acting as a base reacts with water (acting as an acid).** - **Equation:** \( \text{NH}_3 + \text{H}_2\text{O} \rightleftharpoons \text{NH}_4^+ + \text{OH}^- \) - **\( K_{eq} = \) [Calculate and enter result here] 2. **Ammonia acting as an acid reacts with water (acting as a base).** - **Equation:** \( \text{NH}_3 + \text{H}_2\text{O} \rightleftharpoons \) [Complete the equation] - **\( K_{eq} = \) [Calculate and enter result here] **Determine Reaction Prevalence:** Which reaction is more important (i.e., prevalent) in an aqueous solution of ammonia? - [ ] ammonia acting as a base - [ ] ammonia acting as an acid **Data Table:** - **Species \(pK_a\):** - \( \text{NH}_3 \): 35 - \( \text{NH}_4^+ \): 9.25 - \( \text{H}_2\text{O} \): 15.74 - \( \text{H}_3\text{O}^+ \): -1.74 Use this information to solve the given problems and understand the concepts of acid-base equilibria in the context of ammonia's reactions with water.
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