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2. In the reaction 2 Fe(s) + 3/2 0,(g) 2 Fe,0;(s) a. Write the equilibrium constant expression b. When the system is at equilibrium, what could be done to cause a shift to the left? c. What direction would the reaction shift if the concentration of oxygen were increased?

2. In the reaction 2 Fe(s) + 3/2 0,(g) 2 Fe,0;(s) a. Write the equilibrium constant expression b. When the system is at equilibrium, what could be done to cause a shift to the left? c. What direction would the reaction shift if the concentration of oxygen were increased?

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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2. In the reaction 1 of 7 2 Fe(s) + 3/2 0,(g) 2 Fe,0,(s) a. Write the equilibrium constant expression b. When the system is at equilibrium, what could be done to cause a shift to the left? c. What direction would the reaction shift if the concentration of oxygen were increased? 3. The reaction below is known as base hydrolysis: NH,(aq) + H,O(1)2 NH,(aq) + OH(aq) K = 1.8 x 105 a. Does the equilibrium position lie to the right, left, or middle? Explain. b. Demonstrate that the following concentrations satisfy the equilibrium constant:
Transcribed Image Text:2. In the reaction 1 of 7 2 Fe(s) + 3/2 0,(g) 2 Fe,0,(s) a. Write the equilibrium constant expression b. When the system is at equilibrium, what could be done to cause a shift to the left? c. What direction would the reaction shift if the concentration of oxygen were increased? 3. The reaction below is known as base hydrolysis: NH,(aq) + H,O(1)2 NH,(aq) + OH(aq) K = 1.8 x 105 a. Does the equilibrium position lie to the right, left, or middle? Explain. b. Demonstrate that the following concentrations satisfy the equilibrium constant:
2 2 of 7 [NH,] = 0.10 M [NH,] = 1.0 M [OH] = 1.8 x 10° M c. Why is the knowledge of H,0 not needed in answering part b? d. Assuming constant temperature, Is the following solution at equilibrium? Explain. [NH.] = 0.20 M [NH,1 = 0.50 M [OH] = 1.8 x 10° M Introduction This experiment investigates reaction quotient Q, a quantitative predictor of equilibrium and reaction chift The reaction Cuntient O has the came form as the eguilibrium constant K For the
Transcribed Image Text:2 2 of 7 [NH,] = 0.10 M [NH,] = 1.0 M [OH] = 1.8 x 10° M c. Why is the knowledge of H,0 not needed in answering part b? d. Assuming constant temperature, Is the following solution at equilibrium? Explain. [NH.] = 0.20 M [NH,1 = 0.50 M [OH] = 1.8 x 10° M Introduction This experiment investigates reaction quotient Q, a quantitative predictor of equilibrium and reaction chift The reaction Cuntient O has the came form as the eguilibrium constant K For the
Expert Solution
Step 1 Equilibrium Constant Of Reaction

A) Equilibrium Constant Of Reaction

K = 1[O2]3/2

Fe2O3  and Fe not considered in reaction, because they are solids

 

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