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Compare two alternatives, A and B, on the basis of a present worth evaluation using i = 14.00% per year and a study period of 8 years. (Include a minus sign if necessary.) Alternative First Cost Annual Operating Cost Overhaul in Year 4 Salvage Value Life A $-17000 $-5000 $0 $2800 4 years B $-41000 $-9000 $-3550 $8200 8 years The present worth of alternative A is $ Alternative (Click to select) ▾ is selected. (Click to select) B A and that of alternative B is $

Compare two alternatives, A and B, on the basis of a present worth evaluation using i = 14.00% per year and a study period of 8 years. (Include a minus sign if necessary.) Alternative First Cost Annual Operating Cost Overhaul in Year 4 Salvage Value Life A $-17000 $-5000 $0 $2800 4 years B $-41000 $-9000 $-3550 $8200 8 years The present worth of alternative A is $ Alternative (Click to select) ▾ is selected. (Click to select) B A and that of alternative B is $

ENGR.ECONOMIC ANALYSIS
ENGR.ECONOMIC ANALYSIS
14th Edition
ISBN:9780190931919
Author:NEWNAN
Publisher:NEWNAN
Chapter1: Making Economics Decisions
Section: Chapter Questions
Problem 1QTC
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Compare two alternatives, A and B, on the basis of a present worth evaluation using i = 14.00% per year and a study period of 8 years. (Include a minus sign if necessary.) Alternative First Cost Annual Operating Cost Overhaul in Year 4 Salvage Value Life A $-17000 $-5000 $0 $2800 4 years B $-41000 $-9000 $-3550 $8200 8 years The present worth of alternative A is $ Alternative (Click to select) ▾ is selected. (Click to select) B A and that of alternative B is $
Transcribed Image Text:Compare two alternatives, A and B, on the basis of a present worth evaluation using i = 14.00% per year and a study period of 8 years. (Include a minus sign if necessary.) Alternative First Cost Annual Operating Cost Overhaul in Year 4 Salvage Value Life A $-17000 $-5000 $0 $2800 4 years B $-41000 $-9000 $-3550 $8200 8 years The present worth of alternative A is $ Alternative (Click to select) ▾ is selected. (Click to select) B A and that of alternative B is $
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