Compare three alternatives on the basis of their capitalized costs at /= 13.00% per year and select the best alternative. (Include aminus sign if necessary.)AlternativeEFFirst Cost$-75000$-320000AOC, per Year$-40000$-12000Salvage Value$13000$6300024Life, YearsThe capitalized cost of alternative E is $ 372511.40The best alternative isEG$-1025000$-6000$40000000,alternative F is $ 373668.61, and alternative G is $ -1071153.85

To determine the best option among the three alternatives based on capitalized costs, we calculated…

Answered: Compare three alternatives on the basis…

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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What is the best alternative using incremental Analysis? Use MARR = 15% A B C Capital Investment $ 2,000 7,000 4,200 Annual Revenues 3,200 8,000 6,000 Аппиal Costs 2, 100 5, 100 4,000 Market Value at the end of useful life 100 600 420 Useful Life (in years) 10 10 10 The correct ranking of Alternative is Blank 1 Select Alternative Blank 2 Note: Do not put comma, unit of measure and limit your answer to two decimal places. Ex: A-B-C
Can some one please help me to answer each question correctly? please and thank you.
Question 6 For alternatives shown in the table below and on the basis of their capitalized costs CC and an interest rate of 10% per year. Answer the follc better option: Alternative A First cost, $ Maintenance costs, $ per year Salvage value, $ Periodic costs, $ every 10 years Life, years 31,580 5,000 2,000 282,963 13,000 10,000 10,000 4. CC for alternative A=
A Cost $4000 $2000 $6000 $1000 $9000 Annual benefit 639 410 761 117 750 Useful life, in years 20 20 20 20 20 i* 15% 20% 11.1% 9.9% 5.45% Perform incremental ROR analysis to select best one. MARR=6%; (P/A, 6%, 20) = 11.47 %3D
Can some one please help me to solve the following question. Please and thank you
For alternatives shown in the table below and on the basis of their capitalized costs CC and an interest rate of 10% per year. Answer the following questions to select the better option: Alternative 45,025 5.000 Fist cost 5 249.854 13,000 Maintenance costs, 1 per year Salvage valu Periodic costs Severy 10 years e years 2.000 10,000 10.000 4. CC for alternative A
:[A] { > Incremental analysis ([ B Alternative], [B wins ]): C A company considering 2 different machines at MARR at 12% Both life spans = 10 years Initial Cost Annual Operating lost Benefits per yin ar Salvage Value \table MM If you are and of frying investment to company decide More than 2 alternatives if the additional increment is worth while, compare Alternative: A Incremental analysis (Alternative) pairs then B C A MARR Company at Considering 2 different machines at 12% Both life spans = 10 years. M/C X м/с у Initial Cost 160000 285000 Annual Operating Cost Benefits per year Salvage Value 45 000 90000 45000 105000 20000 40000
Compare the alternatives C and D on the basis of a present worth analysis using an interest rate of 13% per year and a study period of 10 years. Alternative C $-46,000 $4,000 $-1,300 $6,000 10 First Cost AOC, per Year Annual Increase in Operating Cost, per Year Salvage Value Life. Years The present worth of alternative C is $1 (Click to select) offers the lower present worth. HELIME BIEN D $-20,000 $-7,500 $-100 $1,300 5 and that of alternative D is $ A
M2.
Complete the following analysis of cost alternatives and select the preferred alternative. The s A D Сapital investment $15,000 S16,000 $13,000 $18,000 Annual costs Market value 250 300 500 100 1,000 1,300 1,750 2,000 at EOY 10 FW(12%) -$49,975 –$53,658 ??? –$55,660 tudy period is 10 years and the MARR = 12% per %3D year.
A project is being planned that has an initial investment at time 0, annual revenuesand expenses, and a salvage value at the end of the project lifespan (20 years). The financialvalues are summarized below:Initial investment amount at time 0 $150,000Estimated annual revenue $34,500 per yearEstimated annual expenses $8,700 per yearEstimated salvage value at end of lifespan $10,000Minimum attractive rate of return (MARR) 15%a. Calculate the capital recovery amount CR(i%).b. Using the annual worth (AW) method, determine whether purchasing the equipmentis economically justified.c. Repeat part (a) using the internal rate of return (IRR) method based on annual worth(AW).d. Using the present worth (PW) method, determine the break-even time period afterwhich purchase of the equipment generates a profit. (Find N when PW = 0) year period.
Which alternatives can be eliminated immediately in the first step of incremental rate of return analysis, if MARR = 10.0%? Do-nothing A B C D First cost 10 $6,000 $4,500 $9,500 $9,500 Annual 0 998 829 1,716 1,384 benefit Life 10 yrs ROR 10.5% 13.0% 12.5% 7.5% D only not enough information попе D and C

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