Compare the magnitudes of the equilibrant vectors measured from the experiment withthose obtained from the graphical and component methods.Example: A: 200 g 60° above +x axisB: 300 g 45° above -x axisC: 400 g 30°below -x-axisA, A cos a = 1.96 N x cos 60° = 0.98 NB₂B cos b = 2.94 N x cos 135º = -2.08 NC, C cos g = 3.92 N x cos 210°= -3.39 NR₂-A, + B + C₂ = -4.49 NA, A sin a = 1.96 N x sin 60° = 1.70 NByB sin b = 2.94 N x sin 135º = 2.08 NC, C sin g = 3.92 N x sin 210° = -1.96 NRy= Ay+ By + Cy = 1.82 NQuestions:I: (a) A: 200 g along +x axisB: 100 g 45° above -x axisA₂ = A cos a =B₂ =B cos b =R₂-A₂+ B₁₂=A₂ = A sin a =B, = B sin b =R₂ = A + B₂ =R=(R₂. R₂):_ QuadrantR = √ (R₂²+R₂²) =Direction:q=tan [R, /R.](c)A: 100 g along -y axisB: 200 g along -x axisA = A cos a =B = B cos b =R₂-A₂+ B₂ =A = A sin a =B, B sin b =R=A, +B₂ =R=(R₁, R₂): QuadrantR = √ (R₂²+R₂²) =Direction:q tan¹ [R, /R] II: (a) A: 150 g 60° along +y axisB: 200 g 45° above -x axisC: 100 g 30° below -x axisA₂ = A cos a =B, =B cos b =C₁ = C cos g =R₂-A₂+B+C₂A, = A sin a =B, =B sin b =C₂ = C sin g =R₂ = A + B + C =R=(R₁, R₂):R= √ (R₂²+R²) =QuadrantDirection:q=tan [R, R.]1(c) A: 200 g along +y axisB: 100 g 60° above +x axisC: 200 g 45° below +x axisA₁ = A cos a =B=B cos b =C₁=C cos g =R₂-A₂+B+C₂A₁ = A sin a =B, =B sin b =C₁ = C sin g =R= A + B + C₂ =R=(R₁, R₂): _R=√(R₂²+R₂²) =Direction:q=tan¹ [R₂/R₂] =Quadrant

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Compare the magnitudes of the equilibrant vectors measured from the experiment with those obtained from the graphical and component methods. Example: A: 200 g 60° above +x axis B: 300 g 45° above -x axis C: 400 g 30°below -x-axis A = A cos a = 1.96 N x cos 60° = 0.98 N B₂B cos b = 2.94 N x cos 135º = -2.08 N C, C cos g = 3.92 N x cos 210°= -3.39 N R₂-A, + B + C₂ = -4.49 N A, A sin a = 1.96 N x sin 60° = 1.70 N By B sin b = 2.94 N x sin 135º = 2.08 N C, C sin g = 3.92 N x sin 210° = -1.96 N R₂ = Ay+ By + Cy = 1.82 N Questions: I: (a) A: 200 g along +x axis B: 100 g 45° above -x axis A₁ = A cos a = B₂ =B cos b = R₂-A₂+ B₂ = A = A sin a = B, = B sin b = R₂ = A + B₂ = R=(R₂. R₂):_ Quadrant R = √ (R₂²+R₂²) = Direction:q tan¹ [R, /R.] (c) A: 100 g along -y axis B: 200 g along -x axis A = A cos a = B, = B cos b = R₂-A₂+B₂ = A = A sin a = B, B sin b = R=A, +B₂ = R=(R₁, R): Quadrant R = √ (R₂²+R₂²) = Direction:q tan [R, /R]

Compare the magnitudes of the equilibrant vectors measured from the experiment with those obtained from the graphical and component methods. Example: A: 200 g 60° above +x axis B: 300 g 45° above -x axis C: 400 g 30°below -x-axis A = A cos a = 1.96 N x cos 60° = 0.98 N B₂B cos b = 2.94 N x cos 135º = -2.08 N C, C cos g = 3.92 N x cos 210°= -3.39 N R₂-A, + B + C₂ = -4.49 N A, A sin a = 1.96 N x sin 60° = 1.70 N By B sin b = 2.94 N x sin 135º = 2.08 N C, C sin g = 3.92 N x sin 210° = -1.96 N R₂ = Ay+ By + Cy = 1.82 N Questions: I: (a) A: 200 g along +x axis B: 100 g 45° above -x axis A₁ = A cos a = B₂ =B cos b = R₂-A₂+ B₂ = A = A sin a = B, = B sin b = R₂ = A + B₂ = R=(R₂. R₂):_ Quadrant R = √ (R₂²+R₂²) = Direction:q tan¹ [R, /R.] (c) A: 100 g along -y axis B: 200 g along -x axis A = A cos a = B, = B cos b = R₂-A₂+B₂ = A = A sin a = B, B sin b = R=A, +B₂ = R=(R₁, R): Quadrant R = √ (R₂²+R₂²) = Direction:q tan [R, /R]

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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