Combustion of gasoline releases almost all of the carbonit contains as CO₂, the major greenhouse gas. As a simplifica-tion, assume that gasoline consists of eight-C alkanes (average d=0.74 g/mL). How many metric tons of CO₂ are released in ayear by an SUV that gets 15 mpg and is driven 18,000 miles?

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Combustion of gasoline releases almost all of the carbonit contains as CO₂, the major greenhouse gas. As a simplifica-tion, assume that gasoline consists of eight-C alkanes (average d=0.74 g/mL). How many metric tons of CO₂ are released in ayear by an SUV that gets 15 mpg and is driven 18,000 miles?

Expert Solution
Step 1

The general reaction of combustion of gasoline, as follows:

2 C2H18 (l) +25 O2(g)  16 CO2 (g)+18 H20 (g)

First calculate the volume of gasoline of 18000 miles in Liters as follows:

18000 mi y 1 gal 15 mi4qt1gal1L1.057 qt = 4541.15 L/y

Now calculated the mass of gasoline by its density

Density is the ration of mass to the volume.

Density = MassVolume

Mass = density x Volume

0.74gmL×4541.15 L×1000mL1.0 L

= 3360710 g

Then calculate the number of moles of gasoline by its molar mass:

The number of moles of gasoline; C8H18 = Amount of C8H18Molar of C8H18

                                                              = 3360710 g114.22 g/ mol

                                                              = 29423.13 mol C8H18

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