How many secondary carbons are in the following hydrocarbon molecule? C-C- с C13 Umu. С с J-U L с - C 1 с-с J-U C

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:**

How many secondary carbons are in the following hydrocarbon molecule?

**Diagram Explanation:**

The molecule depicted consists of a chain and branches of carbon (C) atoms. Specifically, there is a central chain of three carbon atoms:

1. The central carbon atom in this chain is connected to one carbon above and one carbon below.
2. Each outer carbon atom in the main chain is connected to another carbon atom each, extending the structure.

Secondary carbon atoms are those bonded to two other carbon atoms. By analyzing the diagram:

- The central carbon in the main chain is a secondary carbon as it is bonded to two other carbon atoms in the chain.
- Check each carbon atom to determine if it is connected to exactly two other carbon atoms.

With this in mind, count the number of secondary carbon atoms present in the molecule for your answer.
Transcribed Image Text:**Question:** How many secondary carbons are in the following hydrocarbon molecule? **Diagram Explanation:** The molecule depicted consists of a chain and branches of carbon (C) atoms. Specifically, there is a central chain of three carbon atoms: 1. The central carbon atom in this chain is connected to one carbon above and one carbon below. 2. Each outer carbon atom in the main chain is connected to another carbon atom each, extending the structure. Secondary carbon atoms are those bonded to two other carbon atoms. By analyzing the diagram: - The central carbon in the main chain is a secondary carbon as it is bonded to two other carbon atoms in the chain. - Check each carbon atom to determine if it is connected to exactly two other carbon atoms. With this in mind, count the number of secondary carbon atoms present in the molecule for your answer.
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