Combined Spectra 14.46 Identify the C3 H5Br isomers on the basis of the following information: (a) Isomer A has the 'H NMR spectrum shown in 4 Figure 14.49. (b) Isomer B has three peaks in its 13C NMR spectrum: 8 32.6 (CH2); 118.8 (CH2 ); and 134.2 (CH). (c) Isomer C has two peaks in its 13C NMR spectrum: ô 12.0 (CH2) and 16.8 (CH). The peak at lower field is only half as intense as the one at higher field. 10 9 8 7 4 3 2 1 Chemical shift (8, ppm)

Combined Spectra 14.46 Identify the C3 H5Br isomers on the basis of the following information: (a) Isomer A has the 'H NMR spectrum shown in 4 Figure 14.49. (b) Isomer B has three peaks in its 13C NMR spectrum: 8 32.6 (CH2); 118.8 (CH2 ); and 134.2 (CH). (c) Isomer C has two peaks in its 13C NMR spectrum: ô 12.0 (CH2) and 16.8 (CH). The peak at lower field is only half as intense as the one at higher field. 10 9 8 7 4 3 2 1 Chemical shift (8, ppm)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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2. The compound with the closed formula C4H9Br gives the following 1H NMR data. Write the clear formula of the compound with reasons. 1.0 ppm (triplet, 3 H); 1.7 ppm (dublet, 3H); 1.8 ppm (multiplet, 2H); 4.2 ppm (multiplet, 1H)
III) Can 1H NMR spectroscopy be used to differentiate between the two compounds? Briefly explain why or why not. Predict the 1H NMR spectrum for each compound (include integration, multiplicity, and approximate chemical shift). For each set, be sure that you put them in a data table format!
13.45 Propose structures for the two compounds whose 'H NMR spectra are shown. (a) C4H9B1 Chem. Rel. alle shift area 1.05 6.00 1.97 1.00 3.31 2.00 TMS O ppm 10 8. 7 6 3 2 Chemical shift (6) (b) C4H§C12 Chem. Rel. shift area 1.56 3.00 2.13 2.00 3.72 2.00 4.25 1.00 TMS 10 9. 8. 7 6 4 3 2 1 O ppm Chemical shift (8) Intensity Intensity
Cc.18.
Please don't provide handwritten solution ......
A molecule of the molecular formula C5H11Br gives rise to the NMR spectrum below. When reacted with NaOH and water, it forms a product which by NMR has 2 protons 1H at 5.4 ppm and 1H at 5.5 ppm each having a J coupling of 17 Hz. (other protons also present) The product also has an IR stretch at 1550 cm1. Provide the structures of the starting material (1 pt) and product (2 pts) NaOH H20 C5H1,Br 6H triplet 4H quintet 1H quintet 10 8 7 6. 4 3 1 HSP-06-347 ppm
Use the NMR tables & to predict the range (ppm) where each compound should absorb.
Question 7
Cyclohex-2-enone has two protons on its carbon–carbon double bond (labeled Ha and Hb) and two protons on the carbon adjacent to the double bond (labeled Hc). (a) If Jab = 11 Hz and Jbc = 4 Hz, sketch the splitting pattern observed for each proton on the sp2 hybridized carbons. (b) Despite the fact that Ha is located adjacent to an electron-withdrawing C = O, its absorption occurs upfield from the signal due to Hb (6.0 vs. 7.0 ppm). Offer an explanation.