Coherent light that falls on a double-slit produces a fifth order minimum at an angle of 35°. Determine the angle of the 2nd order maximum and the 3rd order minimum.
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A: "Since you have asked multiple questions, we will solve the first question for you. If you want any…
Q: A) Light of wavelength 587 nm illuminates a single 0.70 mm wide slit. At what distance from the slit…
A: It is given that, λ=587 nmd=0.70 mmy=1.58 mm
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A: The wavelength of the monochromatic light is, The width of the slit is, The separation between the…
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A: Given Wavelength of the light is given as λ=495 nm=495×10-9 m Width of the slit is d=0.180…
Q: passes through two parallel slits separated by a distance of 1.42 μm. Calculate the wavelength of…
A: Angular position of third maximum = 600 = 60×π/180 =1.047 radian Separation between slits = 1.42 μm…
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A: Lightwave is an electromagnetic wave; hence, the wave propagation direction is perpendicular to the…
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A: Step 1: Step 2: Step 3: Step 4:
Q: c) A grating has exactly 8000 slits uniformly spaced over 2.54 cm and is illuminated by light from a…
A: Given:- Total number of slits N=8000 Total width of the slit is d=2.54 cm=2.54cm×1 m100 cm=0.0254m…
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- White light is directed perpendicular to an oil film (n = 1.45). Calculate the minimum non-zero thickness of the film required to eliminate blue (450nm) reflections.The second-order dark fringe in a single-slit diffraction pattern is 1.40 mm from the center of the central maximum. Assuming the screen is 85.8 cm from a slit of width 0.685 mm and assuming monochromatic incident light, calculate the wavelength of the incident light.A light with wavelength λ = 565 nm falls on a pair of closely separated slits. The first dark fringe of the interference pattern is at an angle θ = 3.25 degrees from the central maximum. a) Solve for the numerical value of d in mm.
- Monochromatic light of wavelength 441 nm is incident on a narrow slit. On a sereen 2.00 m away, the distance between the second diffraction minima and the central maxima is 1.50 cm. Calculate the angle of diffraction 0 of the second minima and the width of the slit.A single slit of width 4.50 x 10 ºm produces a first-order dark fringe at some angle. If the width of the slit is now changed to 3.08 × 10-ºm, a second-order dark fringe is found at three times the previous angle. What is the wavelength of the light?When the double slits are a great distance from the screen in a double-slit setup, it can be shown that the position of the mth bright fringe from the central maximum fringe is given by the equation y(m) = (m?L)/d . Calculate the wavelength of light (in nm) that produces fringes that are 7.52 mm apart on a screen 7.39 m from double slits separated by 0.120 mm
- Light passes through two parallel slits separated by a distance of 1.98 μm. Calculate the wavelength of light in units of nm if the third-order maximum is at an angle of 60.0 degrees.At what angle in degrees is the first-order maximum for 450-nm wavelength blue light falling on double slits separated by 0.0480 mm?A diffraction pattern is produced on a screen 1.40 m from a single slit, using monochromatic light of wavelength 5.00 x 102 nm. The distance from the center of the central maximum to the first - order maximum is 3.00 mm. Calculate the slit width. Hint: Assume that the first - order maximum is halfway between the first - and second - order minima.
- In a double-slit experiment, d 21um and the wavelength of the light is A = 431nm. The intensity of light at the center of the central fringe is measured to be 21 kW -. Determine the intensity at a point that is at an angle of 1.4° from m? the center of the central fringe lin HW m?). (Use the ideal double slit intensity formula)A double slit experiment using 532 nm light produces an interference pattern with the 1st order maxima separated by an angle of 0.115° from the central maxima. At what distance away should a viewing screen be placed such that the 1st and 2nd order maxima are separated by 6.00 mm?