Monochromatic light is at normal incidence on a plane transmission grating. The first-order maximum in the interference pattern is at an angle of 11.3°. What is the angular position of the fourth-order maximum?
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A: Part c:
Monochromatic light is at normal incidence on a plane transmission grating. The first-order maximum in the interference pattern is at an angle of 11.3°. What is the angular position of the fourth-order maximum?
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- At what angle (in degrees) is the fifth order maximum for 450nm wavelength blue light falling on double slits separated by 0.0380 mm?A slit of width 0.20 mm is illuminated with monochromatic light of wavelength 480 nm, and a diffraction pattern is formed on a screen 1.0 m from the slit. a) What is the width of the central maximum? b) What are the widths of the second- and third-order maxima?Problem 2: Consider light that has its third minimum at an angle of 23.6° when it falls on a single slit of width 3.55 μm. Randomized Variables 9 = 23.6° w = 3.55 um D Find the wavelength of the light in nanometers. λ=1 sin() cos() cotan() asin() atan() acotan() tanh() cosh() O Degrees Hints: 2% deduction per hint. Hints remaining: 2 Submit tan() JU acos() E sinh() cotanh() Radians Hint ( + 7 8 9 4 5 6 1 0 VO BACKSPACE Feedback 2 3 All content © 2022 Expert TA, LLC DEL HOME END I give up! Feedback: 2% deduction per feedback. CLEAR
- What is the highest-order maximum for 383 nm light falling on double slits separated by 24.0 µm?Problem 2: Consider a 470 nm wavelength blue light falling on a pair of slits separated by 0.045 mm. At what angle (in degrees) is the first-order maximum for the blue light? 0 = || sin() cos() cotan() asin() atan() acotan() cosh() tanh() O Degrees O Radians tan() acos() sinh() cotanh() ED π () 7 E ^^ 4 5 6 8 9 HOME + 1 2 VO BACKSPACE 63 DEL END CLEARA diffraction grating has a grating constant of 415 lines/mm. If composite light with wavelengths of 601 nm and 461 nm are incident upon the grating, what is there angular separation in the 1st order spectrum? Answer this with a positive number of degrees.
- The coherence length of an ordinary white light source can be increased if we place a color filter in front of the source, so that the light that passes through the filter is somewhat monochromatic. The minimum wavelength of the emerging light is 546 nm. What is the maximum wavelength in order for the coherence length to be 0.1110 mm?The full width at half-maximum (FWHM) of a central diffraction maximum is defined as the angle between the two points in the pattern where the intensity is one-half that at the center of the pattern. (See figure (b).) (a) Does the intensity drop to one-half the maximum value when sin²α = a²/2? (b) Is a = 1.39 rad (about 80°) a solution to the transcendental equation of (a)? (c) Is the FWHM AÐ = 2sin¹(0.442 A/a), where a is the slit width? Calculate the FWHM of the central maximum for slit width (d) 1.17 A, (e) 5.03 A, and (f) 11.7 A. 20 20 Relative intensity 15 10 0.8 0.6 a=2 0.4 0.2 5 05 8 (degrees) (a) 10 15 20 20 Relative intensity 1.0 0.8 0.6 -A0- 0.4 0.2 a= 52 20 15 10 5 0 5 10 15 20 (degrees) (b)Monochromatic coherent light of amplitude E, and angular frequency w passes through three parallel slits, each sepa- rated by a distance d from its neighbor. (a) Show that the time-averaged intensity as a function of the angle 0 is I(0) = I (2nd sin e 1+ 2 cos max (b) Explain how this expression describes both the primary and the secondary maxima. (c) Determine the ratio of the intensities of the primary and secondary maxima. Hint: See Problem 16.