Answered: Making reference to Figure bellow, what… | bartleby

Related questions

Question

Making reference to Figure bellow, what is the smallest thickness (t) resulting in
destructive interference when viewed from above? Assume monochromatic light
of wavelength 750 nm (in vacuum). A) Find the thickness assuming the angle of
incidence is perpendicular to the surface. B) Find the thickness if we don't make
this assumption and the angle of incidence (to the perpendicular) is 15°.
15°
n=1.00
n=1.40
n = 1.60

Expert Solution

Step by step

Solved in 3 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

The wavelengths of the visible spectrum are approximately 400nm (violet) to 700nm (red). Find the angular width of the first-order visible spectrum produced by a transmission diffraction grating with 555 lines per millimeter when white light falls normally on the grating.Give your answer in degrees.
a) Prove that a 26000 line/ cm diffraction grating cannot produce a maximum for visible light; b) Determine the longest wavelength for which this grating can produce the first-order maximum.
You will view a source of white light through a diffraction grating that has 1000 lines/mm. (a) Find the angles that contain the visible spectrum at 1st order. (b) You can’t see the entire spectrum at 2nd order. What is the last wavelength that is visible, assuming you can see out to 90 degrees. What color is that?
Dear pro Hand written solution is not allowed.
Please asap
In an interference experiment using a monochromatic source emitting light of wavelength 1, the fringes are produced by two long, narrow slits separated by a distance d. The fringes are formed on a screen which is situated at a distance D >> d.Write down an expression for the fringe width w. Please use "*" for products (e.g. B*A), "/" for ratios (e.g. B/A) and the usual "+" and "-" signs as appropriate. Use "lambda" (without the quotes) for 1 in the equation box. For example, use d*lambda for d2. Please use the "Display response" button to check you entered the answer you expect. w=
Intense white light is incident on a diffraction grating that has 454 lines/mm. (a) What is the highest order in which the complete visible spectrum can be seen with this grating? (Enter 1 for first order, 2 for second order, etc.) (b) What is the angular separation between the violet edge (400 nm) and the red edge (700 nm) of the first order spectrum produced by the grating? answer in °
a) What would be the angular position of the third dark fringe from the central maximum, if a 600nm light is incident on a double slit with a slit separation of 2µm? b) If the previous problems double slit also had a slit width of 0.5µm, would would the intensity fraction be at an angular position of 40 degrees?
A monochromatic source of light of wavelength λ, is incident on a slit of width a. Obtain an expression to represent the angle of the 4th diffraction minimum. Hint: Think about Huygens construction with the single slit divided into four equal length sections acting as sources of secondary waves. Write down a general expression for the nth minimum angle. If λ =500 nm, a = 4 μm, determine the angle of the 2nd minimum.
The limit to the eye's acuity is actually related to diffraction by the pupil. What is the angle between two just-resolvable points of light for a 2.75 mm diameter pupil, assuming the average wavelength of 539 nm? angle between two points of light: Take the result to be the practical limit for the eye. What is the greatest possible distance a car can be from a person if he or she can resolve its two headlights, given they are 1.40 m apart? greatest distance at which headlights can be distinguished: m What is the distance between two just-resolvable points held at an arm's length (0.900 m) from a person's eye? distance between two points 0.900 m from a person's eye: m
Find the distance in nm between two slits that produces the first minimum for 415-nm violet light at an angle of 17.5°.
In a double-slit experiment, d 21um and the wavelength of the light is A = 431nm. The intensity of light at the center of the central fringe is measured to be 21 kW -. Determine the intensity at a point that is at an angle of 1.4° from m? the center of the central fringe lin HW m?). (Use the ideal double slit intensity formula)