CO(g)+2H2(g)⇄CH3OH(g)K=2.2×104at298K A stoichiometric mixture of CO(g) and H2(g) was allowed to react in two different 2.0L rigid containers at a constant temperature of 298K. The reaction is represented by the equation above. Diagram 1 represents the uncatalyzed reaction and diagram 2 represents the catalyzed reaction one hour after the reactants were mixed. Which of the following correctly explains the experimental results represented in the particle diagrams? A Although the reaction is thermodynamically favorable because ΔG°<0 based on the value of K, only the catalyzed reaction could proceed in one hour because its reactant molecules had a higher average kinetic energy. B Although the reaction is thermodynamically favorable because ΔG°<0 based on the value of K, only the catalyzed reaction could proceed in one hour because it has a lower activation-energy reaction pathway. C The reaction is not thermodynamically favorable because ΔG°>0 based on the value of K, but the addition of a catalyst improved the orientation of the reactants during collisions, allowing the catalyzed reaction to proceed in one hour. D The reaction is not thermodynamically favorable because ΔG°>0 based on the value of K, but the catalyzed reaction could proceed in one hour because it has a lower ΔH and a higher

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter5: Introduction To Chemical Equilibrium

Section: Chapter Questions

Problem 5.22E: 5.22. True or false: If for a gas-phase reaction, then all equilibrium partial pressures of...

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CO(g)+2H2(g)⇄CH3OH(g)K=2.2×104at298K

A stoichiometric mixture of CO(g) and H2(g) was allowed to react in two different 2.0L rigid containers at a constant temperature of 298K. The reaction is represented by the equation above. Diagram 1 represents the uncatalyzed reaction and diagram 2 represents the catalyzed reaction one hour after the reactants were mixed.

Which of the following correctly explains the experimental results represented in the particle diagrams?

A Although the reaction is thermodynamically favorable because ΔG°<0 based on the value of K, only the catalyzed reaction could proceed in one hour because its reactant molecules had a higher average kinetic energy.

B Although the reaction is thermodynamically favorable because ΔG°<0 based on the value of K, only the catalyzed reaction could proceed in one hour because it has a lower activation-energy reaction pathway.

C The reaction is not thermodynamically favorable because ΔG°>0 based on the value of K, but the addition of a catalyst improved the orientation of the reactants during collisions, allowing the catalyzed reaction to proceed in one hour.

D The reaction is not thermodynamically favorable because ΔG°>0 based on the value of K, but the catalyzed reaction could proceed in one hour because it has a lower ΔH and a higher

Diagram 1
No Catalyst
Reactants
Products
Diagram 2
8.
With Catalyst
Reactants
Products
H = O O=

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