12. In the Ostwald process for oxidizing ammonia, a variety of products is possible - N₂, N₂O, NO, and NO₂- depending on the conditions. One possibility is: NH3(g) + O₂(g) = NO(g) + H₂O (g) Kp = 2.11 x 10¹⁹ at 700 K For the decomposition of NO2 at 700 K, NO2(g) = NO(g) + O2(g) Kp = 0.524 at 700 K What is K, for the oxidation of NH3(g) to NO2(g)? 13. The decomposition of N₂O4 to NO₂ is represented by the equilibrium reaction equation below N2O4(g) 2 NO2 (g) If 1.75 moles of N₂O4 is injected in a 1.5 L vessel and at equilibrium 25% N₂O4 is dissociated, what is the equilibrium constant for this reaction?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
12. In the Ostwald process for oxidizing ammonia, a variety of products is possible - N2, N₂O, NO, and NO₂-
depending on the conditions. One possibility is:
NH3(g) + O₂(g) = NO(g) + H₂O (g) Kp = 2.11 x 10¹⁹ at 700 K
For the decomposition of NO2 at 700 K,
NO₂(g) = NO(g) + O2(g) Kp = 0.524 at 700 K
What is Kp for the oxidation of NH3(g) to NO2(g)?
13. The decomposition of N₂O4 to NO₂ is represented by the equilibrium reaction equation below
N2O4(g) 2 NO2 (g)
If 1.75 moles of N₂O4 is injected in a 1.5 L vessel and at equilibrium 25% N₂O4 is dissociated, what is the
equilibrium constant for this reaction?
Transcribed Image Text:12. In the Ostwald process for oxidizing ammonia, a variety of products is possible - N2, N₂O, NO, and NO₂- depending on the conditions. One possibility is: NH3(g) + O₂(g) = NO(g) + H₂O (g) Kp = 2.11 x 10¹⁹ at 700 K For the decomposition of NO2 at 700 K, NO₂(g) = NO(g) + O2(g) Kp = 0.524 at 700 K What is Kp for the oxidation of NH3(g) to NO2(g)? 13. The decomposition of N₂O4 to NO₂ is represented by the equilibrium reaction equation below N2O4(g) 2 NO2 (g) If 1.75 moles of N₂O4 is injected in a 1.5 L vessel and at equilibrium 25% N₂O4 is dissociated, what is the equilibrium constant for this reaction?
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 5 images

Blurred answer
Knowledge Booster
Chemical Equilibrium
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY