Code A summation=0; for i=1:2:99 summation-summation+i*(i+1); end disp(summation) Code C x=[1:2:99]; y=[2:2:100]; res=x*y'; disp(res) Code D Code B x=linspace (1,100,50); y=linspace (2,100,50); z=x.*y; res=sum(z); disp(res) k=0; s=[]; while k < 100 s=[s k*k+1]; k=k+2; end res=sum(s); disp(res)
Code A summation=0; for i=1:2:99 summation-summation+i*(i+1); end disp(summation) Code C x=[1:2:99]; y=[2:2:100]; res=x*y'; disp(res) Code D Code B x=linspace (1,100,50); y=linspace (2,100,50); z=x.*y; res=sum(z); disp(res) k=0; s=[]; while k < 100 s=[s k*k+1]; k=k+2; end res=sum(s); disp(res)
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
Problem 25RE
Related questions
Question
100%
You want to determine the sum of the products 1*2 + 3*4 + ... + 97*98 + 99*100 with the help of MATLAB. Given are 4 different approaches, but not all of them yield the correct result. With which of the presented MATLAB codes is it possible to compute the correct result? (There might be more than one correct answer)
![Code A
summation=0;
for i=1:2:99
summation-summation+i*(i+1);
end
disp(summation)
Code C
x=[1:2:99];
y=[2:2:100];
res=x*y';
disp(res)
Code D
Code B
x=linspace (1,100,50);
y=linspace (2,100,50);
z=x.*y;
res=sum(z);
disp(res)
k=0;
s=[];
while k < 100
s=[s k*k+1];
k=k+2;
end
res=sum(s);
disp(res)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4810b3f8-7174-4e11-ad5b-d1003066dd42%2Fa2643ab9-762e-456b-850a-265fbc1d1d17%2Fcwv2pu_processed.png&w=3840&q=75)
Transcribed Image Text:Code A
summation=0;
for i=1:2:99
summation-summation+i*(i+1);
end
disp(summation)
Code C
x=[1:2:99];
y=[2:2:100];
res=x*y';
disp(res)
Code D
Code B
x=linspace (1,100,50);
y=linspace (2,100,50);
z=x.*y;
res=sum(z);
disp(res)
k=0;
s=[];
while k < 100
s=[s k*k+1];
k=k+2;
end
res=sum(s);
disp(res)
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