Code A summation=0; for i=1:2:99 summation-summation+i*(i+1); end disp(summation) Code C x=[1:2:99]; y=[2:2:100]; res=x*y'; disp(res) Code D Code B x=linspace (1,100,50); y=linspace (2,100,50); z=x.*y; res=sum(z); disp(res) k=0; s=[]; while k < 100 s=[s k*k+1]; k=k+2; end res=sum(s); disp(res)

Code A summation=0; for i=1:2:99 summation-summation+i(i+1); end disp(summation) Code C x=[1:2:99]; y=[2:2:100]; res=xy'; disp(res) Code D Code B x=linspace (1,100,50); y=linspace (2,100,50); z=x.y; res=sum(z); disp(res) k=0; s=[]; while k < 100 s=[s kk+1]; k=k+2; end res=sum(s); disp(res)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

100%

You want to determine the sum of the products 1*2 + 3*4 + ... + 97*98 + 99*100 with the help of MATLAB. Given are 4 different approaches, but not all of them yield the correct result. With which of the presented MATLAB codes is it possible to compute the correct result? (There might be more than one correct answer)

Code A
summation=0;
for i=1:2:99
summation-summation+i*(i+1);
end
disp(summation)
Code C
x=[1:2:99];
y=[2:2:100];
res=x*y';
disp(res)
Code D
Code B
x=linspace (1,100,50);
y=linspace (2,100,50);
z=x.*y;
res=sum(z);
disp(res)
k=0;
s=[];
while k < 100
s=[s k*k+1];
k=k+2;
end
res=sum(s);
disp(res)

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