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Use base-ten blocks to illustrate 111+5. 111 has flat(s), long(s), and unit(s). Starting with the flats, there are set(s) of 5 flats with Converting the remaining flats to longs gives a total of remaining. Converting the remaining longs to units gives a total of remaining. Therefore, the quotient is with a remainder remaining. long(s), which leads to unit(s), which leads to set(s) of 5 longs with set(s) of 5 units with

Use base-ten blocks to illustrate 111+5. 111 has flat(s), long(s), and unit(s). Starting with the flats, there are set(s) of 5 flats with Converting the remaining flats to longs gives a total of remaining. Converting the remaining longs to units gives a total of remaining. Therefore, the quotient is with a remainder remaining. long(s), which leads to unit(s), which leads to set(s) of 5 longs with set(s) of 5 units with

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Use base-ten blocks to illustrate 111+5. unit(s). 111 has flat(s), long(s), and Starting with the flats, there are set(s) of 5 flats with Converting the remaining flats to longs gives a total of remaining. Converting the remaining longs to units gives a total of remaining. Therefore, the quotient is with a remainder remaining. long(s), which leads to unit(s), which leads to set(s) of 5 longs with set(s) of 5 units with
Transcribed Image Text:Use base-ten blocks to illustrate 111+5. unit(s). 111 has flat(s), long(s), and Starting with the flats, there are set(s) of 5 flats with Converting the remaining flats to longs gives a total of remaining. Converting the remaining longs to units gives a total of remaining. Therefore, the quotient is with a remainder remaining. long(s), which leads to unit(s), which leads to set(s) of 5 longs with set(s) of 5 units with
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