Please help me with these two questions. I am not understanding how to do it Click and drag the steps to show that at least three of any 25 days chosen must fall in the same month of the year.ResetHence, three chosen days must fall in thesame month.There will be 3-12 = 36 chosen days in 12months.Assume there were at most two chosendays falling into any one month.Then, there will be at most 2-12 = 24chosen days in 12 months.This contradicts the assumption that we have25 days.Assume there were at most three chosendays falling in the same month.S Use the following building blocks in the right column to assemble a direct proof that the product of two odd numbers is odd.Not all blocks belong in the proof.Suppose that the product of two odd numbers is odd.Then n = 2k + 1 and m = 2k + 1 for some integer k.Suppose that nm is odd.Then n = 2k + 1 for some integer k andm 2q +1 for some integer q.PBy definition of an odd integer, that means that nm is odd.By multiplying these equations,we obtain nm = (2k + 1)(2q + 1).Suppose that n and m are odd numbers.Distributing, we get nm=2(2kq +k+q) +1.Reset

In discrete mathematics, there are two basic methods for proving a statement is true: proof by…

Click and drag the steps to show that at least three of any 25 days chosen must fall in the same month of the year. Reset Hence, three chosen days must fall in the same month. There will be 3-12 36 chosen days in 12 months. Assume there were at most two chosen days falling into any one month. Then, there will be at most 2-12 = 24 chosen days in 12 months. This contradicts the assumption that we have 25 days. Assume there were at most three chosen days falling in the same month.

Click and drag the steps to show that at least three of any 25 days chosen must fall in the same month of the year. Reset Hence, three chosen days must fall in the same month. There will be 3-12 36 chosen days in 12 months. Assume there were at most two chosen days falling into any one month. Then, there will be at most 2-12 = 24 chosen days in 12 months. This contradicts the assumption that we have 25 days. Assume there were at most three chosen days falling in the same month.

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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