XC++456 ▾Subscribe to see which companies asked this question.Related Topics ▾Similar Questions ▼789,1 class Solution {2 public:int3▾012345101112135:1914First Unique Charact...leetcode.com{i++) {15 };LeetCode}firstUniqChar(string s) {unordered_map m;for (int i=0; i

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class Solution { public: int i++) { { firstUniqChar(string s) { unordered_map m; for (int i=0; i

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Implement a __setitem__ function that also supports negative indices. For example: W = L2(Node(10, Node(20, Node(30))))print W[ 10, 20, 30 ] W[1]=25print W[ 10, 25, 30 ] W[-1]=35print W[ 10, 25, 35 ] Complete the code: def L2(*args,**kwargs): class L2_class(L): def __getitem__(self, idx): <... YOUR CODE HERE ...> def __setitem__(self, idx, value): <... YOUR CODE HERE ...> return L2_class(*args,**kwargs) W = L2(Node(10, Node(20, Node(30))))print(W)W[1]=25print(W)W[-1]=35print(W)
Sorting Create a MyLinkedList class with inner Node class, data fields, and the insert(element) method. Implement a toString method to return all nodes in MyLinkedList. Implement a recursive sorting and a non-recursive sorting method.
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import numpy as np%matplotlib inlinefrom matplotlib import pyplot as pltimport mathfrom math import exp np.random.seed(9999)def is_good_peak(mu, min_dist=0.8): if mu is None: return False smu = np.sort(mu) if smu[0] < 0.5: return False if smu[-1] > 2.5: return False for p, n in zip(smu, smu[1:]): #print(abs(p-n)) if abs(p-n) < min_dist: return False return True maxx = 3ndata = 500nset = 10l = []answers = []for iset in range(1, nset): npeak = np.random.randint(2,4) xs = np.linspace(0,maxx,ndata) ys = np.zeros(ndata) mu = None while not is_good_peak(mu): mu = np.random.random(npeak)*maxx for ipeak in range(npeak): m = mu[ipeak] sigma = np.random.random()*0.3 + 0.2 height = np.random.random()*0.5 + 1 ys += height*np.exp(-(xs-m)**2/sigma**2) ys += np.random.randn(ndata)*0.07 l.append(ys) answers.append(mu) p6_ys = lp6_xs =…
void func(vector<string>& names){ sort(names.begin(), names.end()); //(a) for(int i = names.size() - 1; i > 0; --i){. //(b) if(names[i] == names[i - 1]){ names[i] = move(names.back()); names.pop_back(); } } } What are the reasons or consequences for the programmer’s choice to loop backwards in the line marked (b), and under what circumstances would the algorithm behave differently if that line were replaced with: for (int i = 1; i < names.size(); ++i) ? What would change?
public ArrayList<Bus> loadBuses(String bfile) { ArrayList<Bus> buses = new ArrayList<>(); try { Scanner scanner = new Scanner(new File(bfile)); while (scanner.hasNextLine()) { String[] line = scanner.nextLine().split(" "); if (line.length < 4 || line.length > 7) { throw new IllegalArgumentException("Invalid input format"); } String name = line[1]; int size = Integer.parseInt(line[1]); int price = Integer.parseInt(line[2]); int level = Integer.parseInt(line[3]); Ministry ministry = null; if (line.length > 5) { ministry = new Ministry(line[5]); } int competitorArea, numSecurity, barArea; Bus bus; SportsBus sportsBus; PartyBus partyBus;…
Both ArrayList and LinkedList are inefficient for searches, take linear time. Explain why this occurs in these data structures
Computer Science Can someone convert this python code to racket/scheme programming language.
public static BinaryTreeNode buildBST(int[] keys){ Arrays.sort(keys);return sortedBuildBST(keys,0,keys.length-1);}public static BinaryTreeNode sortedBuildBST(int[] keys, int start, int end){if(start > end){return null;}int mid = (start+end)/2;BinaryTreeNode node = new BinaryTreeNode(keys[mid]);node.left = sortedBuildBST(keys,start,mid-1);node.right = sortedBuildBST(keys,mid+1, end);return node;} Analyze the run time and prove that the constructed BST is no deeper than 1+log2 n levels.
convert C++ STL code into Python:int main(){ // empty map container map<int, int> gquiz1; // insert elements in random order gquiz1.insert(pair<int, int>(1, 40)); gquiz1.insert(pair<int, int>(2, 30)); gquiz1.insert(pair<int, int>(3, 60)); gquiz1.insert(pair<int, int>(4, 20)); gquiz1.insert(pair<int, int>(5, 50)); gquiz1.insert(pair<int, int>(6, 50)); gquiz1.insert(pair<int, int>(7, 10)); // printing map gquiz1 map<int, int>::iterator itr; cout << "\nThe map gquiz1 is : \n"; cout << "\tKEY\tELEMENT\n"; for (itr = gquiz1.begin(); itr != gquiz1.end(); ++itr) { cout << '\t' << itr->first << '\t' << itr->second << '\n'; } cout << endl; return 0;}
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