Consider the given table, compute D1 *Classffxfdcf sinterval34 - 52443172-4-16453 - 71362186-3-972 - 9081405-2-101291 - 109121001200-1-1224110 - 12826119309450129 - 1473138414153148 - 16615794221259167 - 185117617660ΣfxN =6065892995.25O 126.31O 126.1965.17of

From the given table, we get Here, n=60D1 class : Class with (n/10)th value of the observation in cf…

Answered: Class f fx d fd cf s interval 34 - 52 4…

A First Course in Probability (10th Edition)

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Chapter1: Combinatorial Analysis

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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Class f fx d fd cf s interval 34 - 52 4 43 172 -4 -16 4 53 - 71 3 62 186 -3 -9 7 72 - 90 5 81 405 -2 -10 12 91 - 109 12 100 1200 -1 -12 24 110 - 128 26 119 3094 50 129 - 147 3 138 414 1 3 53 148 - 166 6 157 942 2 12 59 167 - 185 176 176 3 60 fx fd N = 60 6589 29 95.25 126.31 126.19 65.17 3.