Secondsfreq.Lower BoundariesClass Mark(x)fx Cumulative Frequency(cf)(x-x̅)2f(x-x̅)266-70465.5682722144.4889177.955661-65860.563504172.788922.311256-60755.558406911.088977.622351-55250.553106269.3888138.7776 ∑f = 21 ∑fx = 1288 ∑ f(x-x̅)2 = 416.67Look for the: (check if all the data except the seconds and frequency are correct)a) mean timeb) median timec) moded) variancee) standard deviationf) range

According to Policy we can answer only first three part for remaining please reposed the question.

Answered: Seconds freq. Lower Boundaries Class…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Seconds	freq.	Lower Boundaries	Class Mark (x)	fx	Cumulative Frequency (cf)	(x-x̅)²	f(x-x̅)²
66-70	4	65.5	68	272	21	44.4889	177.9556
61-65	8	60.5	63	504	17	2.7889	22.3112
56-60	7	55.5	58	406	9	11.0889	77.6223
51-55	2	50.5	53	106	2	69.3888	138.7776
	∑f = 21			∑fx = 1288			∑ f(x-x̅)²= 416.67

Look for the: (check if all the data except the seconds and frequency are correct)

a) mean time

b) median time

c) mode

d) variance

e) standard deviation

f) range

Definition Definition Middle value of a data set. The median divides a data set into two halves, and it also called the 50th percentile. The median is much less affected by outliers and skewed data than the mean. If the number of elements in a dataset is odd, then the middlemost element of the data arranged in ascending or descending order is the median. If the number of elements in the dataset is even, the average of the two central elements of the arranged data is the median of the set. For example, if a dataset has five items—12, 13, 21, 27, 31—the median is the third item in ascending order, or 21. If a dataset has six items—12, 13, 21, 27, 31, 33—the median is the average of the third (21) and fourth (27) items. It is calculated as follows: (21 + 27) / 2 = 24.

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