Determine the diameter of the A325 bearing-type bolts required in the bolted bracket shown. Use the elastic unit area method and compare with the instantaneous center of rotation method. Pu= 102 kN (LRFD), Pu = 67 kN (ASD). W12 X 35 e = 254 Pu -12.7 MM plate A36 76 76 1. LRFD Method 2. ASD Method O O O 76 O O ALL DIMENSIONS ARE IN MM

Determine the diameter of the A325 bearing-type bolts required in the bolted bracket shown. Use the elastic unit area method and compare with the instantaneous center of rotation method. Pu= 102 kN (LRFD), Pu = 67 kN (ASD). W12 X 35 e = 254 Pu -12.7 MM plate A36 76 76 1. LRFD Method 2. ASD Method O O O 76 O O ALL DIMENSIONS ARE IN MM

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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please solve 1.2
3. A single angle tension member L89x89x9.5 with an area of 1,800mm2 connected to a gusset plate with 22 mm diameter bolts as shown in the figure. A36 steel is used with Fy=248 MPa and Fu= 400 MPa. The service loads are 150 KN dead load and 65 KN live load. Investigate the adequacy of the member. Diameter of hole is 3 mm bigger than bolt diameter and use net area equal to 85% of the computed net area. Neglect block shear. a. Check using ASD Load Combination b. Check using LRFD load combination
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please solve 1.1
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SITUATION I A lapped bolted lension member is shown. Diameter of bolts are 22 mm and the plate material is A36 steel Fy = 275 MPа, Fи 3 415 МPа. Assume the fasteners are adequate and do not control the tensile capacity. Diameter of hole is 2.5 mm bigger than the diameter of bolt. 12 :: 350 50 100 100 50 50 1. Determine the tensile capacity of the lapped joint based on gross area. a. 252.656 kN c. 866.250 kN b. 202.125 kN d. 693.000 kN 2. Determine the net Area for the tensile capacity of the lapped joint. а. 3318 тm? c. 5250 mm? b. 1554 mm? d. 1824 mm? 3. Determine the tensile capacity of the lapped joint based on the net area. a. 752.856 kN C. 866.250 kN b. 688.845 kN d. 1039.500 kN
Material Strengths: Fy = 248 MPa, F = 400 MPa For the two lines of bolt holes, the pitch is the value that will give a net area DEFG equal to the one along ABC. The diameter of the holes is 22 mm. The thickness of the plate is 12 mm. Determine the LRFD design tensile strength based on yielding on gross area. D A to 50 1 ÓB 50 50 ic O 410 kN O 464 kN O 446 kN O 401 KN F IG Pitch Pitch KISS|Y
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please solve 1.3
Determine the load capacity of the angle LRFD. USE NSCP 2015.
P4.002 Three bolts are used in the connection shown in the figure. The thickness of plate (1) is 15 mm. The ultimate shear strength of the bolts is 350 MPa, and the ultimate bearing strength of plate (1) is 375 MPa. Determine the minimum bolt diameter required to support an applied load of P = 155 kN if a minimum factor of safety of 2.8 is required with respect to both bolt shear and plate bearing failure. Answer: dbolt min = (1) mm